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Sonbull [250]
3 years ago
11

Which statement about the self-ionization of water is correct? a. Two water molecules interact to form a water molecule and a hy

droxide ion. b. Two water molecules interact to form a hydronium ion and a hydroxide ion. c. Two water molecules interact to form two hydronium ions. d. Two water molecules interact to form two hydroxide ions.
Chemistry
2 answers:
Norma-Jean [14]3 years ago
8 0
B. Two water<span>molecules interact to form a hydronium ion and a hydroxide ion. This is basically the definition of the process.</span>
bearhunter [10]3 years ago
5 0

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Water is the compound which is formed by the covalent bonding of hydrogen and oxygen atoms. The chemical formula for this compound is H_2O

Self-ionization of water is defined as the process in which 2 water molecules react together to produce hydroxide ion and hydronium ion.

The equation for the self ionization of water molecule follows:

2H_2O(l)\rightarrow H_3O^+(aq.)+OH^-(aq,)

By Stoichiometry of the reaction:

2 moles of water molecules react together to produce 1 mole of hydronium ion and 1 mole of hydroxide ion.

Hence, the correct answer is Option b.

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Derivative for tan(x)
Maksim231197 [3]

Answer:

  • sec² (x)

Explanation:

Use the trigonometric ratio definition of the tangent function and the quotient rule.

  • tan(x) = sin(x) / cos(x)

Quotient rule: the derivative of a quotient is:

  • [the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²

  • (f/g)' = [ g×f' - f×g'] / g²

So,

  • tan(x)' = [ sin(x) / cos(x)]'
  • [ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²

                                   = [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²

                                   = [ cos²(x) + sin²(x) ] / cos²(x)

                                   = 1 / cos² (x)

                                   = sec² (x)

The result is that the derivative of tan(x) is sec² (x)

4 0
2 years ago
A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and
Lunna [17]

The pH of the unknown solution is 3.07.

<u>Explanation:</u>

<u>1.Find the cell potential as a function of pH</u>

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0   lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

<u>2. Find the Q  value</u>

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

E cell= 2.303 × 8.314 CK mol (inverse)  × 298.15

K × 2pH /2×96 485  C⋅mol

( inverse)

E cell= 0.0592 V × pH

<u>3. Finding the pH value</u>

E cell= 0.0592 V × pH

pH = E cell/ 0.0592 V= 0.182V/ 0.0592V

pH=3.07

The pH of the unknown solution is 3.07.

7 0
3 years ago
What evidence supports Bohr’s claim that an electron is found only in specific energy levels around the nucleus of the atom. And
Lorico [155]

Energy Levels of Electrons. As you may remember from chemistry, an atom consists of electrons orbiting around a nucleus. ... They are restricted to orbits with only certain energies. Electrons can jump from one energy level to another, but they can never have orbits with energies other than the allowed energy levels.

4 0
3 years ago
Read 2 more answers
16. The concentration of a solution of potassium hydroxide is determined by titration with nitric
____ [38]

Answer:

M_{base}=0.709M

Explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

KOH+HNO_3\rightarrow KNO_3+H_2O

We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

n_{acid}=n_{base}

That in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, solving the molarity of the base (KOH), we obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} =\frac{0.498M*42.7mL}{30.0mL}\\ \\M_{base}=0.709M

Regards.

3 0
3 years ago
Please help and match them
alina1380 [7]
The answers from top to bottom right to left are
3,1,2,4
7 0
2 years ago
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