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oksian1 [2.3K]
3 years ago
5

A small ball is attached to one end of a rigid rod with negligible mass. The ball and the rod revolve in a horizontal circle wit

h the other end of the rod at the center. The path of the ball has a constant linear speed. The force exerted by the rod is 0.5 N. The centripetal acceleration is 0.5 m/s2 . What is the mass of the ball, in kg?
Physics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

mass of the ball will be 1 kg

Explanation:

We have given force F = 0.5 N

This force must be equal to the centripetal force for the ball to revolve in the circle

So F=F_C=0.5N

Centripetal acceleration is given as a_c=0.5m/sec^2

We have to calculate the mass of the ball

We know that force is given by

F_C=ma_c

So 0.5=m\times 0.5

m = 1 kg

So mass of the ball will be 1 kg

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Answer: The HUMAN EYE

Explanation:

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In the human eye, the IRIS helps to regulate the amount of rays passing through the pupil to the lens by either contracting or dilating in light or dark environment respectively. While in the camera, the DIAPHRAGM controls the amount of light entering the camera.

The PUPIL serves as the passage for light into the eye while in the camera, the APERTURE does the same.

The photosensitive surface in the eye is the YELLOW SPOT while in the camera, the photosensitive surface is the PHOTOGRAPHIC FILM.

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3 years ago
A student has a thin copper beaker containing 100 g of a pure metal in the solid state. The metal is at 215°C, its exact melting
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Answer:

The metal will melt but their will be no change in temperature.

Explanation:

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3 years ago
Scientist Jordan makes a discovery and publishes the results for other scientists to read. Scientist Leesha tries to repeat the
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3 years ago
1500 kg Peugeot car is traveling at 16.67 m s ⁻¹ and accelerates to 30.56 m s ⁻¹ for 2 minutes. Calculate the impulse of the car
Elis [28]

Answer:

2084 kg*m/s

Explanation:

Impulse is change in momentum

Mathematically;

Impulse, J= F*t=mΔv   where

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2 years ago
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egoroff_w [7]

Answer:

4. both blocks will both have the same amount of kinetic energy.

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