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oksian1 [2.3K]
3 years ago
5

A small ball is attached to one end of a rigid rod with negligible mass. The ball and the rod revolve in a horizontal circle wit

h the other end of the rod at the center. The path of the ball has a constant linear speed. The force exerted by the rod is 0.5 N. The centripetal acceleration is 0.5 m/s2 . What is the mass of the ball, in kg?
Physics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

mass of the ball will be 1 kg

Explanation:

We have given force F = 0.5 N

This force must be equal to the centripetal force for the ball to revolve in the circle

So F=F_C=0.5N

Centripetal acceleration is given as a_c=0.5m/sec^2

We have to calculate the mass of the ball

We know that force is given by

F_C=ma_c

So 0.5=m\times 0.5

m = 1 kg

So mass of the ball will be 1 kg

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This is a question on my physics test :)
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Answer:

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Explanation:

Data obtained from the question include:

Mass of substance (ms) = 170 g

Initial temperature of substance (Ts) = 120 °C

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Initial temperature of water (Ts) = 10 °C

Temperature of the mixture (T2) = 12.6 °C

Density of water = 1 g/mL

Specific heat capacity of water (Cw) = 4200J/Kg°C

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Mass of water = 0.2 Kg

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MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

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Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

Initial temperature of substance (Ts) = 120 °C

Specific heat capacity of substance (Cs) =..?

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

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840(2.6) + 0.17Cs(– 107.4) = 0

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Rearrange

2184 = 18.258Cs

Divide both side by the coefficient of Cs i.e 18258

Cs = 2184/18.258

Cs = 119.6 J/Kg°C

Therefore, the specific heat capacity of the substance is 119.6 J/Kg°C

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