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3 years ago

Some dams are designed to make electricity. How do dams make electricity?

1 answer:

4 0

They make electricity by directing the flow of water past turbines causing them to spin. When the turbines spin it creates a current in the wire, electricity.

Good Luck! Hope I helped:)

You might be interested in

Two positive point charges are 4.9cm apart. If the electric potential energy is 70.0 μJ, what is the magnitude of the force betw

ExtremeBDS [4]

Hi there!

Recall the following:

$V \text{ (Electric Potential Energy) } = \frac{kq_1q_2}{r}\\\\F_E = \frac{kq_1q_2}{r^2}$

k = Coulomb's Constant (Jm/C²)

q = Charge (C)
r = distance between charges (m)

To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):

$F_E = \frac{70}{0.049} = \boxed{1428.57 \mu J}$

6 0

2 years ago

Which device in a car helps to protect riders from the effects of inertia in the event of an acident

Schach [20]

The seatbelt, as it prevents you from flying out of your window.

if this was the appropriate answer make sure to mark as the brainliest!
-procklown

5 0

3 years ago

Read 2 more answers

A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 10^6

Anestetic [448]

Answer:

7.36 × 10^22 kg

Explanation:

4 0

2 years ago

What is the efficiency of a tractor that has a work output of 300j and a work input of 400j

Sauron [17]

<h3><u>Answer;</u></h3>

= 75 %

<h3><u>Explanation</u>;</h3>

To measure efficiency of a machine, compare the work output to work input.

Efficiency = Work output/ work output × 100 %

= 300/400 × 100

= 75 %

5 0

3 years ago

One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction

goblinko [34]

Answer:

The magnitud of the force is 124.8N.

Explanation:

First we have to find the value of the static friction coefficient, when the external force F is applied to upper block (i will call it A Block) we have a free body diagram as the one shown in the figure i attached, so since this block has no aceleration in any direction the force F should be equal to the friction force between A and B block, one we noticed this we can use the equation for the Friction force to find the coefficient:

$0=F-FrictionAB$

$F=FrictionAB=Nab*$ μs

and again, since the block has no acceleration the normal between A and B block should be equal to the weigth of the first block, so we have:

$0=Nab-W$

$Nab=W=mg$

replacing this we have:

$F=$ μs $*Nab=$ μs* $mg=41.6N$

and μs $=41.6N/(mg)$

now it's time to see the free body diagram for the b block, if we now apply the F force to the B block the diagram should look like in the figure.

the color of the arrow gives you an idea of where the force comes from, the blue ones comes from the B block, the red ones from the A block and the brown ones from the ground.

now for the B block you can see two friction forces, one for the ground and one for the A block, both of these directed bacwards, and two normal forces, again one for the ground and one for the A block but the normal force for the A block is aiming downwards.

again we use the fact that the block is not accelerating in any direction so the sum of the forces in x and y direction have to be 0, so:

$F-Friction1(ground)-Friction2(AB)=0$