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Svetach [21]
3 years ago
5

Maddison hid 12 of her sister's birthday gifts around the house. If this was 15% of the gifts, how many total gifts did her sist

er have?
Mathematics
2 answers:
I am Lyosha [343]3 years ago
4 0

Answer:

80 gifts

Step-by-step explanation:

Maddison hid 12 of her sister's birthday gifts around the house. If this was 15% of the gifts, how many total gifts did her sister have?

Let the Total gifts that her sister has be represented by x

Hence:

15% of x = 12

15/100 × x = 12

15x /100 = 12

Cross Multiply

15x = 100 × 12

15x = 1200

x = 1200/15

x = 80 gifts

Hence, the total gifts her sister has is 80 gifts

Travka [436]3 years ago
4 0

Answer:

80 total gifts

Step-by-step explanation:

Step one:

given data

Maddison hid 12 of her sister's birthday gifts

we are told that 12 gift is 15% of the total gifts

let the total gifts be x

so

=15/100*x= 12

=0.15x= 12

divide both sides by 0.15

x= 12/0.15

x=80 total gifts

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\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\
f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}
\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

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&\uparrow &\uparrow &\uparrow &\uparrow \\
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so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
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