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romanna [79]
3 years ago
14

The difference between diffusion and osmosis is that osmosis deals only with ________.

Chemistry
1 answer:
Nat2105 [25]3 years ago
6 0
Osmosis deals only with D. Water. Diffusion and Osmosis are relatively the same thing besides the fact that water is largely incorporated with the osmosis.
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Which of the graphs below illustrates water boiling in Denver, Colorado? (Altitude 1,600 meters.)
lina2011 [118]

Answer:

  • The graphs that come with this question are in the picture attached.

  • The answer is graph identified with the letter A.

Explanation:

The normal boiling point of water is 100°C. That is the temperature at which water boils when the atmospheric pressure is 1 atm, i.e. at sea level.

The liquids boil when its vapor pressure equals the atmospheric pressure; so the higher the atmospheric pressure the higher the boiling point, and the lower the atmospheric pressure the lower the boiling point.

Since, it is stated that the altitude of Denver, Colorado is 1,600 m, the atmosperic pressure (ther pressure exerted by the columnn of air above the place) is lower than 1 atm (atmospheric pressure at sea level).

Hence, water boiling point in Denver is lower than 100°C.

The graphs shown represent the temperature (T °C) as water is heated. Since when liquids boil their temperature remains constant during all the phase change, the flat portion of the graph represents the time during which the substance is boiling.

In the graph A, the flat portion is below 100°C; in the graph B, the flat portion is at 100 °C; in the graph C the flat part is above 100ªC, and, in graph D, there is not flat part. Then, the only graph that can illustrate water boiling in Denver, Colorado is the graph A.

4 0
3 years ago
A drug is supplied as a 40 mg/ml solution in a 50 ml vial. you need to make 10 ml of a 10 mg/ml solution. how much concentrate w
Ymorist [56]

Answer: -

2.5 mL

Explanation: -

Volume of final solution = 10 mL

Strength of final solution = 10 mg / mL

Amount of drug required = Volume of final solution x strength of final solution

= 10 mL x 10 mg/ mL

= 100 mg.

Strength of supplied drug = 40mg/ mL

Volume of supplied drug required = \frac{100 mg}{40 mg/ mL}

= 2.5 mL

Thus to make 10 ml of a 10 mg/ml solution. 2.5 mL will be needed.

8 0
3 years ago
Identify which of the bonds in calcium hydroxide, Ca(OH)2, are ionic and which are covalent.
ira [324]
<span>The bonds in calcium hydroxide, Ca(OH)2, </span> calcium hydroxide, is formed by ionic bonds between Ca2 and OHA. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
4 0
3 years ago
Read 2 more answers
At a certain concentration of N2 and H2, the initial rate of reaction is 5.0 x 105 M / s. What would the initial rate of the rea
Andreyy89
I’m really sorry I need points I hope you find an answer
6 0
3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
balandron [24]

Answer:

The final temperature of the water is 22.44°C.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-q_1=q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

q_2=m_2c_2\times (T-T_3)

-q_1=q_2  (Law of Conservation of energy)

-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

The final temperature of the water is 22.44°C.

3 0
3 years ago
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