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Anuta_ua [19.1K]
3 years ago
15

What is difference between continuous and discontinuous variations? Give examples for each of it

Physics
1 answer:
mash [69]3 years ago
6 0

Answer:

Examples. Weight, height, and length of organisms are examples of continuous variation while the color of petals, blood groups of animals, the gender of animals, etc. are examples of discontinuous variation.

Explanation:

Hope it helps

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Which of the following is an example of uniform circular motion?
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C. A rocket traveling to the Moon

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What is the difference between gross anatomy and microscopic anatomy?
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There are two major types of anatomy. Gross (macroscopic) anatomy is the study of anatomical structures that can be seen by the eye, such as the external and internal bodily organs. Microscopic anatomy is the study of tiny anatomical structures such as tissues and cells.
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What is the oxidation number of the element Se
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The oxidation number of a monatomic (composed of one atom) ion is the same as the charge of the ion. For example, the oxidation numbers of K+, Se2−, and Au3+ are +1, -2, and +3, respectively. The oxidation number of oxygen in most compounds is −2.

Explanation:

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3 years ago
There are 92 naturally occurring elements. How does this relate to the number of compounds?
raketka [301]

C) Elements combine in different ways to create many more than 92 compounds.

Explanation:

The number of elements we have relates to the compound formation in that, elements combine in different ways to create many more than 92.

Elements are distinct substances that cannot be split up into simpler substances. Such substances are only made up of one kind of atom.

Compounds are substances that are made up of two or more kinds of atoms joined together in a definite grouping.

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  • The number of elements do not increase because new elements are discovered, it is because elements have several ways by they combine.

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3 0
4 years ago
Write the dimension of a / b in the x = at + bt2. Where x is the distance and t is the time?​
Luba_88 [7]

The dimension of a/b where x is the distance and t is the time is T

Given the expression

x = at + bt²

where

x is the distance

t is the time

Based on the homogeneity principle, the expression on the left-hand side must be equal to that on the right. Hence;

x = at

a = \frac{x}{t}

Since x is the distance and distance is measured in metres, the dimension equivalent will be the length 'L'

Since t is the time and time is measured in seconds, the dimension equivalent will be the seconds 'T'

a=\frac{L}{T}

Similarly;

x  = bt²

b=\frac{x}{t^2}\\b=\frac{L}{T^2}

Next is to get a/b;

\frac{a}{b} =  \frac{L}{T} \div \frac{L}{T^2}\\\frac{a}{b} = \frac{L}{T}*\frac{T^2}{L}  \\\frac{a}{b} =\frac{T^2}{T}\\\frac{a}{b} =T

Hence the dimension of a/b is T

4 0
3 years ago
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