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3 years ago

What temperature, in ∘c, is a blackbody whose emission spectrum peaks at 250 nm ?

1 answer:

6 0

Wein's law states that:

Peak wavelength (m)*Temperature (K) = 2.898*10^-3 m.K

In this case, Peak spectrum = 250 nm = 250*10^-9 m

Temperature (K) = (2.898*10^-3)/(250*10^-9) = 11592 K

In °C, Temperature = 11592-273.15 = 11,318.85 °C

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Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to

Anestetic [448]

Your answer should be D.
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5 0

3 years ago

We are given the description of an enclosure that has fencing on 3 sides and can use 3,056 yards of fencing. We are to find the

shusha [124]

Answer:

The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards

Explanation:

Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.

Therefore since we can use 3,056 yards of fencing

Side perpendicular to the river = x and,

Side opposite to the river = y = 3056 - 2x

The area of the rectangle formed (A) = Perpendicular side × Parallel side

∴ A = x(3056 - 2x) = 3056x - 2x²

A = 3056x - 2x²

To maximize the area, A' (dA/dx) = 0

∴ A' = 3056 - 4x = 0

3056 - 4x = 0

4x = 3056

x = 764 yards

y = 3056 - 2x = 3056 - 2(764) = 1528 yards.

Side perpendicular to the river = 764 yards and,

Side opposite to the river = 1528 yards

The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards

5 0

3 years ago

A slingshot fires a pebble from the top of a building at a speed of 17.5 m/s. The building is 31.5 m tall. Ignoring air resistan

Jlenok [28]

Answer:

The speed with which the pebble strikes the ground is 30.4m/s

Explanation:

Initial velocity (u) = 17.5m/s, height (h) = 31.5m, acceleration due to gravity (g) = 9.8m/s^2

V^2 = u^2 + 2gh = 17.5^2 + 2×9.8×31.5 = 306.25 + 617.4 = 923.65

V^2 = 923.65

V = √923.65 = 30.4m/s

6 0

4 years ago

Which part of and organism is preserved in cast and mold fossils

Lubov Fominskaja [6]

Answer:

bones

Explanation:

Bones are is preserved in cast and mold fossils.

Normally the other 'parts of the body' like muscles, ligaments, blood and organs are soft.

5 0

3 years ago

A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b

stepan [7]

The work done by a system kept at constant pressure is given by:
$W=p \Delta V = p (V_f - V_i)$
where
p is the pressure
$V_f$ is the final volume
$V_i$ is the initial volume

If we plug the numbers given by the problem into this equation, we find
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

And since $1 atm \cdot L = 101.3 J$ , we have that the work done is
$W= 1.00 atm \cdot L = 101.3 J$

8 0

3 years ago

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