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Vladimir [108]
3 years ago
14

What temperature, in ∘c, is a blackbody whose emission spectrum peaks at 250 nm ?

Physics
1 answer:
Anettt [7]3 years ago
6 0
Wein's law states that:

Peak wavelength (m)*Temperature (K) = 2.898*10^-3 m.K

In this  case, Peak spectrum = 250 nm = 250*10^-9 m

Temperature (K) = (2.898*10^-3)/(250*10^-9) = 11592 K

In °C, Temperature =  11592-273.15 = 11,318.85 °C
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