The reaction between sodium and chlorine that forms table salt is shown

Roger believes that he is following a healthy regime by taking lots of vitamin E everyday. What property of vitamin E makes Roge

Zanzabum

If you are a plato user the answer is D. vitamin E is fat soluble

6 0

3 years ago

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The half-life of cobalt-60 is 5.3 years. after __________ years, 1/4 of the original amount of cobalt-60 will remain.

cestrela7 [59]

The number of years required for 1/4 cobalt-60 to remain after decay is calculated as follows

after one half life 1/2 of the original mass isotope remains

after another half life 1/4 mass of original mass remains

therefore if one half life is 5.3 years then the years required

= 2 x 5.3years = 10.6 years

4 0

3 years ago

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What is the mass of 0.100 mole of neon? (Watch sf’s)

dimaraw [331]

Answer:

The answer to your question is letter D. 2.02 g

Explanation:

Data

moles of Ne = 0.100

atomic mass of Neon = 20.18 g

Process

1.- Use proportions to find the answer

20.18 g of Ne ------------------ 1 mol of Ne

x ------------------ 0.1 moles

x = (0.1 x 20.18)/1

x = 2.018

2.- Consider the significant figures

0.100 has three significant figures so the answer must be 2.02 g

4 0

3 years ago

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Identify the two main materials that can be found in the inner and outer core layers of the earth.

Mrrafil [7]

A. Iron D. Nickel hope this helps you!

6 0

3 years ago

A gas that was heated to 150 Celsius has a new volume of 1587.4 L. What was its volume when its temperature was 100 Celsius?

sdas [7]

Answer:

$\boxed {\boxed {\sf 1058.3 \ L}}$

Explanation:

We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{T_2}$

The temperature was 100 degrees Celsius, but the volume is unknown.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C}$

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C} * 100 \textdegree C$

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = V_2$

The units of degrees Celsius cancel.

$100 *\frac {1587.4 \ L }{150 } = V_2$

$100 *10.58266667 \ L = V_2$

$1058.266667 \ L = V_2$

The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

$1058.3 \ L = V_2$

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>

6 0

3 years ago