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AleksAgata [21]
3 years ago
8

A voltaic cell consists of a nickel electrode in a solution containing Ni2+ ions, and a copper electrode in a solution containin

g Cu2+ ions. Which is the cell potential? a. E subscript c e l l space end subscript superscript 0 space end superscript equals minus 0.59 V b. E subscript c e l l space end subscript superscript 0 space end superscript equals plus 0.59 V c. E subscript c e l l space end subscript superscript 0 space end superscript equals minus 0.09 V d. E subscript c e l l space end subscript superscript 0 space end superscript equals plus 0.09 V
Chemistry
1 answer:
Marysya12 [62]3 years ago
4 0
First, we write the half equations for the reduction of the chemical species present:

Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V

In order to determine the potential of the cell, we find the difference between the two values. For this:

E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V

The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
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Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

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Where in this case:

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We <u>input the data</u>:

  • 6.13 L * n₂ = 11.3 L * 2.51 mol
  • n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

  • 4.63 - 2.51 = 2.12 moles
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2 years ago
Explain why the first ionization energy K is less than that of Ca
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Answer:

The first ionization energy for K is less than Ca because Ca has a larger effective nuclear charge.

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3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
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Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

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Explanation:

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KonstantinChe [14]

Answer:

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Explanation:

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