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AleksAgata [21]
3 years ago
8

A voltaic cell consists of a nickel electrode in a solution containing Ni2+ ions, and a copper electrode in a solution containin

g Cu2+ ions. Which is the cell potential? a. E subscript c e l l space end subscript superscript 0 space end superscript equals minus 0.59 V b. E subscript c e l l space end subscript superscript 0 space end superscript equals plus 0.59 V c. E subscript c e l l space end subscript superscript 0 space end superscript equals minus 0.09 V d. E subscript c e l l space end subscript superscript 0 space end superscript equals plus 0.09 V
Chemistry
1 answer:
Marysya12 [62]3 years ago
4 0
First, we write the half equations for the reduction of the chemical species present:

Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V

In order to determine the potential of the cell, we find the difference between the two values. For this:

E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V

The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
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When you break an iron magnet into two pieces, you get ____.
Rudiy27

Answer:

two north poles and two south poles

Explanation:

A single magnet has a north pole and a south pole. If it is broken into two pieces, then each of the two pieces will have a north pole and a south pole.

No matter how many times or into how many pieces a magnet is broken, the resulting pieces will have two poles each.

5 0
3 years ago
Read 2 more answers
Determine the number of moles within a sample of 10g of propane(C3H8). Round your answer to 2 decimal places with proper units.
a_sh-v [17]

Given :

10 gram sample of propane( C₂H₈ ).

To Find :

The number of moles of propane in given sample.

Solution :

Molecular mass of propane, M = (2 × 12) + ( 1 × 8 ) gram/mol

M = 32 gram/mol

We know, number of moles is given by :

Number of moles, n = m/M

n = 10/32 mol

n = 0.3125 mol

Therefore, number of moles in given sample is 0.3125 mol.

7 0
3 years ago
2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2
Sergeu [11.5K]

Answer: 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{1.60g}{32g/mol}=0.05moles

2KMnO_4\rightarrow K_2MnO_4+MnO_2+O_2

According to stoichiometry :

As 1 mole of O_2 is given by = 2 moles of KMnO_4

Thus 0.05 moles of O_2 is given by =\frac{2}{1}\times 0.05=0.10moles  of KMnO_4

Mass of KMnO_4=moles\times {\text {Molar mass}}=0.10moles\times 158g/mol=15.8g

Thus 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

5 0
3 years ago
A 70.0-g piece of copper metal at 86.0 ∘c is placed in 50.0 g of water at 16.0 ∘c. The metal and water come to the same temperat
valentina_108 [34]
Copper is current voltage above 40 or 200 . copper useful for motor and some medicine
4 0
3 years ago
What volume of a 2.5 M NaOH solution is required to prepare 2.0 liters of a 0.75M NaOH? A. 2.5 liters B. 6.7 liters C. 0.60 lite
puteri [66]

Answer:

C. 0.60

Explanation:

Mi x Vi = Mf x Vf

2.5 x Vi = 0.75 x 2.0

2.5 x Vi = 1.5

Vi = 1.5 / 2.5

Vi = 0.6 L

8 0
3 years ago
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