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kiruha [24]
3 years ago
13

In the Haber process, nitrogen gas is combined with hydrogen (from natural gas) to form ammonia. If ammonia is formed at 0.345 M

/s, how quickly is the nitrogen gas disappearing
Chemistry
1 answer:
algol133 years ago
6 0

Answer:

r_{N_2}=-0.1725M/s

Explanation:

Hello,

In this case, by means of the law of mass action, we firstly write the described chemical reaction:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

Thus, as ammonia is being formed at 0.345 M/s, nitrogen will be disappearing at (consider law of mass action):

r_{NH_3}=0.345M/s\\\\\frac{1}{-1} r_{N_2}=\frac{1}{-3}r_{H_2}=\frac{1}{2} r_{NH_3}\\\\r_{N_2}=-\frac{1}{2} r_{NH_3}=-\frac{1}{2} *0.345M/s\\\\r_{N_2}=-0.1725M/s

Best regards.

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