Question

In the Haber process, nitrogen gas is combined with hydrogen (from natural gas) to form ammonia. If ammonia is formed at 0.345 M/s, how quickly is the nitrogen gas disappearing

Answer 1

Answer:

$r_{N_2}=-0.1725M/s$

Explanation:

Hello,

In this case, by means of the law of mass action, we firstly write the described chemical reaction:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

Thus, as ammonia is being formed at 0.345 M/s, nitrogen will be disappearing at (consider law of mass action):

$r_{NH_3}=0.345M/s\\\\\frac{1}{-1} r_{N_2}=\frac{1}{-3}r_{H_2}=\frac{1}{2} r_{NH_3}\\\\r_{N_2}=-\frac{1}{2} r_{NH_3}=-\frac{1}{2} *0.345M/s\\\\r_{N_2}=-0.1725M/s$

Best regards.