Answer:
The line segment partitioned two-fifths from A to B is (10,6)
Step-by-step explanation:
First point from A to B is (16,8)
than find the difference between A to B i.e B - A
(1,3)-(16,8) = (-15,-5)
To measure the (2/5) difference we will multiply (-15,-5) with (2/5) which is equal to (-6,-2)
Now Add the difference to the first coordinate (point A) gives
Point of division = (16,8)+(-6,-2)
Point of division = (16-6, 8-2)
Point of division = (10,6)
A = x > -3 and x < 4
B = x >withlineunder -3 and x <withlineunder 4
C = X < - 3 or X > 4
Not 100% sure this is right but
60cm^2
This problem is about the distance between points, in this case, we have to unidimensional coordinates, that is, point O is at -2, and Point V is at 1/2.
It's important to know that the proper way to find the distance here is by subtraction, we need to subtract the final points and the initial point. In math, such subtraction is called "differential" or "variation", just a fancy name.
<h2>Therefore, the distance from O to B is 2.5 units.</h2>
Answer:
No solutions.
Step-by-step explanation:
x - y = 2 <Start with an equation
x - (x + 2) = 2 <Plug in the given y value and solve for x
x - x - 2 = 2 <Combine like terms
0 - 2 = 2 <There are no values of x
No solutions.
