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goldfiish [28.3K]
2 years ago
10

Ytuugtfghrddfghjiuyhhffdfvhj

Physics
2 answers:
irga5000 [103]2 years ago
8 0
Urgnccrfnccntuhcrjfnccnnccntjgjctgc thank you
Tema [17]2 years ago
4 0

Answer:

hwjsjsjsjksksnsjkdkdnnd

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What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?
Evgen [1.6K]

Answer:

Fr = 48 [N] forward.

Explanation:

Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.

∑F = Fr

F_{engine}-F_{brake} =F_{r}\\F_{r}=79-31\\F_{r}=48[N]

The movement remains forward, since the force produced by the movement is greater than the braking force.

3 0
2 years ago
Typically, atoms gain or lose electrons to achieve
nasty-shy [4]

Answer:

Typically, atoms gain or lose electrons to achieve a stable electron configuration.

Explanation:

3 0
3 years ago
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What is the difference between a free body diagram and a vector diagram?​
Murrr4er [49]

Answer:

Free body diagrams are used to describe situations where several forces act on an object. On the other hand Vector diagrams are used to resolve (break down) a single force into two forces acting as right angles to eachother

Explanation:

Hope this helps !

4 0
2 years ago
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The accompanying map shows the route traveled by a school bus.
Shtirlitz [24]

Answer:

C

Explanation:

6 0
3 years ago
An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is W/m². What is the rms
inn [45]

I think your question should be:

An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is

S = 1.23*10^9 W/m^2

What is the rms value of (a) the electric field and

(b) the magnetic field in the electromagnetic wave emitted by the laser

Answer:

a) 6.81*10^5 N/c

b) 2.27*10^3 T

Explanation:

To find the RMS value of the electric field, let's use the formula:

E_r_m_s = sqrt*(S / CE_o)

Where

C = 3.00 * 10^-^8 m/s;

E_o = 8.85*10^-^1^2 C^2/N.m^2;

S = 1.23*10^9 W/m^2

Therefore

E_r_m_s = sqrt*{(1.239*10^9W/m^2) / [(3.00*10^8m/s)*(8.85*10^-^1^2C^2/N.m^2)]}

E_r_m_s= 6.81 *10^5N/c

b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:

B_r_m_s = E_r_m_s / C;

= 6.81*10^5 N/c / 3*10^8m/s;

B_r_m_s = 2.27*10^3 T

8 0
3 years ago
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