Answer:
r2/r1 = 1.3
Explanation:
Electric field is given as:
E = kq/r²
At a distance r1,
226 = kq/(r1)² - - - - - - - - - - - - - (1)
At a distance r2,
134 = kq/(r2)² - - - - - - - - - - - - - (2)
From (1),
kq = 226 * (r1)²
From (2),
kq = 134 * (r2)²
Equating and then solving,
134 * (r2)² = 226 * (r1)²
(r2)²/(r1)² = 226/134
(r2)²/(r1)² = 1.687
=> r2/r1 = 1.3
Answer:
I think it is 1.67
Explanation:
I multiply the 45 and 27 cause it says rate of which means to multiply.
Answer:
1946 ft
Explanation:
The distance is the addition of the distance gotten from both triangles.
d = x + y
d = 1178 ft + 768 ft
d = 1946 ft
Attached is a picture showing how I arrived at the answer
Each successive graph is at a later time. You can see from these graphs how the amplitude of the total electric field changes, but the positions of the crests and troughs (called antinodes) and places of zero field (called nodes) never change.!!!!!!!!!!!!!!!!!
Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
