Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm
His. Curbs I b h bs. H b u b
Grass dear wolf is the right awnser
Answer: the correct option is D (17m).
Explanation: The farthest distance at which a typical "nearsighted" frog can see clearly in air is 17m.
Answer:
Explanation:
If M be mass of moon and m be mass of spacecraft
potential energy of moon -spacecraft system
= - G M m / R where R is radius of orbit of spacecraft
kinetic energy of spacecraft in the orbit
= 1/2 m v² = GMm / 2R
Total energy of spacecraft
= GMm / 2R - G M m / R
= - GMm / 2R
for spacecraft to leave the orbit, energy required
= GMm / 2R
= 6.67259 x 10⁻¹¹ x 7.36 x 10²² x 14800 / (2 x 1.79877 x 10⁶)
= 202035.8 x 10⁵ J .
