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Marat540 [252]
3 years ago
14

Explain why some people see objects nearby clearly, but objects far away appear blurry. Also, explain how this condition can be

corrected.
EDGE 2020
Physics
2 answers:
Maru [420]3 years ago
7 0

Myopia

Explanation:

myopia is a common vision condition in which you can see objects near to you clearly, but objects farther away are blurry. It occurs when the shape of your eye causes light rays to refract incorrectly, focusing images in front of your retina instead of on your retina. It can be corrected corrected with eyeglasses, contact lenses or refractive surgery.

slamgirl [31]3 years ago
7 0

Answer:

the first guy is correct i think

sorry but i needed points

Explanation:

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I am Lyosha [343]

Answer:

9 meters

Explanation:

Given:

Mass of Avi is, m=40\ kg

Spring constant is, k=176,400\ N/m

Compression in the spring is, x=20\ cm=0.20\ m

Let the maximum height reached be 'h' m.

Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.

So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.

Decrease in elastic potential energy is given as:

EPE=\frac{1}{2}kx^2\\EPE=\frac{1}{2}\times 176400\times (0.20)^2\\EPE=88200\times 0.04=3528\ J

Now, increase in gravitational potential energy is given as:

GPE=mgh=40\times 9.8\times h=392h

Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,

392h=3528\\\\h=\frac{3528}{392}\\\\h=9\ m

Therefore, Avi will reach a maximum height of 9 meters.

6 0
3 years ago
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla
dusya [7]

Answer:

C). U_f = \frac{U_0}{2}

Explanation:

As we know that capacitance of a given capacitor is

C = \frac{\epsilon_0 A}{d}

now we know that energy stored in the capacitor plates

U_0 = \frac{Q^2}{2C}

here if all the dimensions of the capacitor plate is doubled

then in that case

C' = \frac{\epsilon_0 (4A)}{2d}

here area becomes 4 times on doubling the radius and the distance between the plates also doubles

So new capacitance is now

C' = 2C

so capacitance is doubled

now the final energy stored between the plates of capacitor is given as

U_f = \frac{Q^2}{2C'}

so the final energy is

U_f = \frac{Q^2}{4C}

U_f = \frac{U_0}{2}

4 0
3 years ago
The cloud of interstellar dust and gas that forms a star is known as a
Alex777 [14]
     The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.
8 0
4 years ago
Read 2 more answers
It requires 49 J of work to stretch an ideal very light spring from a length of 1.4 m to a length of 2.9 m. What is the value of
nadya68 [22]

Answer:

44 N/m

Explanation:

The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m

The work needed to stretch a spring by <em>e</em> is given by

W = \frac{1}{2} ke^2

where <em>k</em> is spring constant.

k = \dfrac{2W}{e^2}

Using the appropriate values,

k = \dfrac{2\times 49\text{ J}}{1.5^2\text{ m}^2} = 43.55\ldots\text{ N/m} \approx 44\text{ N/m}

3 0
3 years ago
Read 2 more answers
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn
Cerrena [4.2K]

Answer:

e. Not enough information to determine

Explanation:

This question is incomplete. Here is the complete question with my solution afterwards;

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)

a. The ladybug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The centripetal force acting on a rotating body or bugs can be written as,

F=mrw^2

m= mass of the corresponding bugs

r= corresponding radial distance of each bug

w= angular speed of the turntable

The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable

F ∝ mr

Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.

Option "e" is correct.

7 0
3 years ago
Read 2 more answers
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