Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = 
= 
= 12m/s
Velocity = 
= = 12m/s due east
Answer:
Explanation:
If the dragster attains the speed equal to that of the car which is moving with constant velocity of v₀ , before the two close in contact with each othe , there will not be collision .
So the dragster starting from rest , must attain the velocity v₀ in the maximum time given that is tmax .
v = u + a t
v₀ = 0 + a tmax
tmax = v₀ / a
The value of tmax is v₀ / a .
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Answer:
32 pounds
Explanation:
The amount of water in the 200 pound person is
200 * 60% = 200*0.6 = 120 pounds
Of the 120 pounds, a third of this is extracellular fluid, the amount of extracellular fluid is
120 / 3 = 40 pounds
20 % of this is in the blood, which amounts to
40 * 20% = 40 * 0.2 = 8 pounds
The rest is interstitial fluid, which is
40 - 8 = 32 pounds
Answer:
a = F/m
Explanation:
So we have to isolate a, in order to do this we need to move m to the other side, and we do that by diving both sides by m, resulting in a = F/m
