As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion. Equation to follow are F = mv²/r "Force of friction" Ff= μsN, Normal N=mg Ff=μsmg. Therfore
mv²/r = μsmg cancel mass "m" The formula to follow will be μs = v²/rg
μs = v²/rg μs = (28.89 m/s²)²/ (65 m)(9.8 m/s²) = 1.31
Answer:
2 m/s
Explanation:
Applying,
The law of conservation of momentum
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.
make V the subject of the equation
V = (mu+m'u')/(m+m')........... Equation 2
From the question,
Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)
Substitute these values into equation 2
V = [(1234×6)+(2468×0)]/(1234+2468)
V = 7404/3702
V = 2 m/s
Answer:
I believe it would be E)none of the above.
Explanation:
The answer is Mars
Mars has a rotational period closest to that of Earth. Mars is roughly longer than a day on Earth. This is by far the closest by over a hundred hours. Other than Jupiter which rotates less than 10 hours. Mars has a rotation of 24.75 hours or 1.03 Earth days.
Explanation:
The given data is as follows.
= 400 K, 
= 500 K,
= 25 kJ = 25000 J (as 1 kJ = 1000 J)
Now, we will calculate the change in entropy as follows.
Putting the given values into the above formula as follows.
= 
= 250 J/K
Hence, we can conclude that change in entropy is 250 J/K.
