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Natasha_Volkova [10]
3 years ago
7

What measures air pressure.?

Physics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
That depends on what type of pressure you are attempting to measure, to measure Atmospheric pressure, you would use a Barometer. To measure things like tires, you could use a Tire Pressure Gauge. For Industrial processes and boilers, you would use a Manometer. For pressure vessels, you would use a Bordon Gauge.   <span />
Contact [7]3 years ago
5 0
Manometers Is your answer for that question.

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This type of star is called the "white dwarf." When a very massive star exhausts its nuclear fuel it explodes as a supernova.

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List 5 plants or animals that the emporer penguin eats
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What do electric power companies deliver to customers
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8 0
3 years ago
Find the ratio of the diameter of aluminium to copper wire, if they have the same
kicyunya [14]

Answer:

1.24

Explanation:

The resistivity of copper\rho_1=2.65\times 10^{-8}\ \Omega-m

The resistivity of Aluminum,\rho_2=1.72\times 10^{-8}\ \Omega-m

The wires have same resistance per unit length.

The resistance of a wire is given by :

R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi (\dfrac{d}{2})^2}\\\\\dfrac{R}{l}=\rho \dfrac{1}{\pi (\dfrac{d}{2})^2}

According to given condition,

\rho_1 \dfrac{1}{\pi (\dfrac{d_1}{2})^2}=\rho_2 \dfrac{1}{\pi (\dfrac{d_2}{2})^2}\\\\\rho_1 \dfrac{1}{{d_1}^2}=\rho_2 \dfrac{1}{{d_2}^2}\\\\(\dfrac{d_2}{d_1})^2=\dfrac{\rho_1}{\rho_2}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{\rho_1}{\rho_2}}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{2.65\times 10^{-8}}{1.72\times 10^{-8}}}\\\\=1.24

So, the required ratio of the diameter of Aluminum to Copper wire is 1.24.

3 0
3 years ago
A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als
Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

V_T = V_1 + V_2

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

V_T = 10 + 10 = \boxed{\text{ D. 20 V}}

6 0
2 years ago
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