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balu736 [363]
3 years ago
6

A bus that was moving at a high speed stopped suddenly. One of

Physics
1 answer:
fiasKO [112]3 years ago
7 0

Answer:

this doesn't make sinces

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Help me please
yarga [219]
1. False
2.False
3.False
4.True
5. True
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3 0
3 years ago
Read 2 more answers
If a car travels 216 kilometers in 4 hours, calculate its speed.
Mariana [72]

Answer:

15 m/s

Explanation:

Speed(m/s) = distance(m)/time(s)

distance = 216 km = 216,000 m

time = 4 hours = 14,400 s

speed = 216000/14400 = 15 m/s

6 0
2 years ago
Read 2 more answers
Look at the advertisement. A poster that reads, "There's more to resistors than resistance. If you're really serious about cost,
ozzi

Options:

universal appeal

flattery

association

bandwagon

Answer: Association

Explanation: Advertisement is a marketing technique through which business organisations utilize the opportunities provided by both the print, electronic and other channels of communication to market a product to the target audience.

Association Advertising is a type of Advertising where certain attributes which have been known to be associated with good and quality products are used to market the products to the target audience.

7 0
4 years ago
Read 2 more answers
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
aliina [53]

Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

W=K_f - K_i

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

K_f is the final kinetic energy

K_i = 66,120 J is the initial kinetic energy

Solving,

K_f = K_i + W = 66,120 + (-36,733)=29,387 J

Now we can find the final speed of the car by using the formula for kinetic energy

K_f = \frac{1}{2}mv^2

where

m = 661 kg is the mass of the car

v is its final speed

Solving for v, we find

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s

3 0
3 years ago
Which equation is used to calculate the electric potential in an electric field from a point charge?
scZoUnD [109]

Answer:

The electric potential (voltage) V produced by a point charge Q, at any point in space, is given by the following equation:

V=k\frac{Q}{r}

Where:

k=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant

r is the distance  

The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.

6 0
3 years ago
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