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gayaneshka [121]
3 years ago
13

Nitrous oxide, NO, decomposes exothermically into nitrogen gas and oxygen gas. When graphing [NO] versus time, a straight line c

an be drawn through the experimental points. From this information, determine the reaction order.
Chemistry
1 answer:
Aleksandr [31]3 years ago
8 0

Answer:

Zero-Order

Explanation:

The exothermic decaying of nitrous oxide at 575° C will lead to N_{2} and   O_{2} as follows:

2N_{2}O → 2N_{2}(g) + O_{2}  (g)

<u>Hot platinum wire in the above reaction would function as a catalyst in the zero-order</u>. However, if the reaction is considered in the gaseous phase, it will be more inclined towards second-order.

In the given scenario(2N_{2}O → 2N_{2}(g) + O_{2}  (g)), <u>the reactant molecules of Nitrous oxide are restricted to the ones which have linked themselves to the catalyst's surface. Once this limited surface is filled, the extra molecules of gas would remain vacant until the previously attached molecules with the surface are decayed entirely</u>.

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When 1 mol of KBr(s) decomposes to its elements, 394 kJ of heat is absorbed. (a) Write a balanced thermochemical equation.
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The balanced thermochemical equation is

KBr ------- K + 1/2 Br2

<h3>What is thermochemical equation? </h3>

A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.

The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :

KBr ----- K + Br2

The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows

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As the heat is absorbed in this reaction therefore, heat is positive.

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KBr ------- K + 1/2 Br2

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How many Moles of NAOH are present in 2.50L of 0.300 M NaOH?
maw [93]
<h3>Answer:</h3>

0.75 moles NaOH

<h3>Explanation:</h3>

We are given;

Volume of NaOH solution = 2.5 Liters

Molarity of NaOH = 0.300 M

We are required to calculate the moles of NaOH

We need to establish the relationship between moles, molarity and volume of a solution.

That would be;

Concentration/molarity = Moles ÷ Volume

Therefore;

Moles = Concentration × Volume

Thus;

Moles of NaOH = 0.300 moles × 2.50 L

                         = 0.75 moles

Therefore, the number of moles of NaOH is 0.75 moles

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