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olga2289 [7]
3 years ago
8

A student the mass of 8 cm3 block of brown sugar to be 12.9 g. What is the density of the brown sugar

Chemistry
1 answer:
antoniya [11.8K]3 years ago
8 0
12,9 g of sugar-----------------8cm3
x g of sugar ------------------- 1cm3
<u>x = 1,613g/cm3 <<< density</u>
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Everyone needs a certain number of ____________ to meet their daily energy needs.
Ganezh [65]

Answer:

The answer is calories.

The average human being needs 2000 calories for them to be energized.

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According to one acid-base theory, a water molecule acts as an acid when the water molecule
Snowcat [4.5K]
According to one acid-base theory, a water molecule acts as an acid when the water molecule (3) donates an H+.
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Which of the following is true about a compound and its elements?
BaLLatris [955]
 They can change properties completely 
They can be separated 
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6 0
3 years ago
Read 2 more answers
1. (8pt) Using dimensional analysis convert 600.0 calories into kilojoules
Ivanshal [37]

Answer:

1. 2.510kJ  

2. Q = 1.5 kJ

Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

1cal=4.184J\\\\1kJ=1000J

Then, we perform the conversion as follows:

600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ

2. Here, we use the general heat equation:

Q=mC(T_2-T_1)

And we plug in the given mass, specific heat and initial and final temperature to obtain:

Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ

Regards!

7 0
2 years ago
The specific heat of zinc is 0.39 J/g*°C. How much energy needed to change the temperature of 34g of zinc from 22°C to 57°C. Is
Svetlanka [38]

Answer:

464.1 J absorbed.

Explanation:

Given data:

Specific heat of zinc =  0.39 J/g°C

Mass of zinc = 34 g

Temperature changes = 22°C to 57°C

Energy absorbed or released = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57°C -  22°C

ΔT = 35°C

Q = m.c. ΔT

Q = 34 g. 0.39 J/g°C. 35°C

Q = 464.1 J

6 0
3 years ago
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