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Flura [38]
3 years ago
12

WDYT a mixture is? Please help

Chemistry
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

A mixture is when two substances are physically combined and can be taken apart.

Explanation:

my words

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Can someone help me check my answers for the mole questions?
Sliva [168]

Answer:

Explanation:

Given data:

Number of particles of phosphorous = 1.2 × 10²⁵

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

Number of particles of phosphorous = 1.2 × 10²⁵ particles

1 mole = 6.022 × 10²³ particles

1.2 × 10²⁵ particles × 1 mole /  6.022 × 10²³ particles

0.1993  × 10² mol

19.93 mole

Q 3:

Given data:

Number of moles of calcium = 0.630 mol

Number of particles = ?

Solution:

The number 6.022 × 10²³ is called Avogadro number.

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ particles of hydrogen

For 0.63 moles:

1 mole = 6.022 × 10²³ particles

0.63 mol × 6.022 × 10²³ particles  / 1 mol

3.79 × 10²³ particles

Q 4:

Given data:

Number of moles = 4 mol

Number of particles = ?

Solution:

The number 6.022 × 10²³ is called Avogadro number.

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ particles of hydrogen

For 4 moles:

1 mole = 6.022 × 10²³ particles

4 mol × 6.022 × 10²³ particles  / 1 mol

24 × 10²³ particles

2.4  × 10²⁴ particles

3 0
4 years ago
The type of chemical bond that involves the transfer of electrons between atoms is a(n) bond.
aev [14]
An ionic bond occurs when an atom transfers or takes Electrons from another atom.
8 0
4 years ago
Read 2 more answers
1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?
Fittoniya [83]
M\ N_2=28g/mol\\
63,8\%--28g\\
100\%--x\\
x=43,89g

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g

3 0
3 years ago
How many molecules of sulfur trioxide are in 78.0 grams?
zalisa [80]

Answer:

b) 5.87 E23 molecules

Explanation:

∴ mm SO3 = 80.066 g/mol

⇒ molecules SO3 = (78.0 g)(mol/80.066 g)(6.022 E23 molec/mol)

⇒ molec SO3 = 5.866 E23 molecules SO3

5 0
3 years ago
How many rings does an alkane have if its formula is c10h16?
stepladder [879]

If it is saturated compound then we can calculate the double bond equivalent which will be equal to the number of rings in the compound

the double bond equivalent can be calculated using following formula

DBE = (C + 1 -\frac{H}{2} - \frac{X}{2} +\frac{N}{2} )

Where

H = number of Hydrogen atoms

C = number of carbon atoms

X= number of halogen atoms

N = number of nitrogen atoms

DBE = (10 + 1  - 16 / 2 ) = 3

Hence there are three rings in the compound

3 0
3 years ago
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