To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration
of the stock solution, V1 is the volume of the stock solution, M2 is the
concentration of the new solution and V2 is its volume.
2 M x V1 = 0.1 M x .5 L
<span>V1 = 0.025 L or 25 mL of the
2 M KCl solution is needed</span>
<span>What would you use if you needed to determine the density of an object?
</span>Balance and Graduate Cylinder
Hope This Helps! <span>\(★ω★)/</span>
Answer:
melting point will be higher than that of pure ethyl acetate
Explanation:
im pretty sute the answer would be number 4.
mark brainliest :)
