Kesley has been hired to set up a network for a large business with ten employees. Which of the factors below will be

The excessive use of the internet and the web for personal use at work is sometimes called ____ .

Elodia [21]

This is called Cyberslacking

7 0

3 years ago

A Web site that allows users to enter text, such as a comment or a name, and then stores it and later display it to other users,

balandron [24]

Answer:

Option(c) is the correct answer.

Explanation:

Cross-site scripting is the type of security breach that are usually found in the software applications.The main objective of cross site scripting it is used by the hackers to exploit the data security.

The cross site scripting is the collection of web pages that enables people to insert the text like comment, name stores it afterwards it save the data and then it appears to the other users.
Others options are incorrect because they are not related to given scenario.

5 0

3 years ago

Read 2 more answers

What is one effective way for employees to keep their skill-sets current

natta225 [31]

Is it a multiple choice answer? if so would like to see the answers as there are TONS of effective ways and if i list one it may not be in that list you have if its multiple choice.

3 0

3 years ago

Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N

Kryger [21]

Answer:

Here is the C++ program.

#include <iostream> //to use input output functions

using namespace std; // to access objects like cin cout

void chessboard(int N){ // function that takes a number N as parameter generates corresponding board

int i, j;

string black = "B"; // B for black squares

string white = "W"; // W for white squares

for(i=1;i<=N;i++){ //iterates through each column of the board

for(j=1;j<=N;j++){ //iterates through each row of the board

if((i+j)%2==0) // if sum of i and j is completely divisible by 2

cout<<black<<" "; //displays B when above if condition is true

else //if (i+j)%2 is not equal to 0

cout<<white<<" "; } // displays W when above if condition is false

cout<<endl; } } //prints the new line

int main(){ //start of the main function

int num; //declares an integer num

cout << "Enter an integer representing the size of the chessboard: "; //prompts user to enter size of chess board

cin >> num; //reads value of num from user

chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0

3 years ago

Input a list of employee names and salaries and store them in parallel arrays. End the input with a sentinel value. The salaries

4vir4ik [10]

Using the knowledge in computational language in JAVA it is possible to write the code being Input a list of employee names and salaries and store them in parallel arrays

<h3>Writting the code in JAVA:</h3>

BEGIN

DECLARE

employeeNames[100] As String

employeeSalaries[100] as float

name as String

salary, totalSalary as float

averageSalary as float

count as integer

x as integer

rangeMin, rangeMax as float

INITIALIZE

count = 0;

totalSalary =0

DISPLAY “Enter employee name. (Enter * to quit.)”

READ name

//Read Employee data

WHILE name != “*” AND count < 100

employeeNames [count] = name

DISPLAY“Enter salary for “ + name + “.”

READ salary

employeeSalaries[count] = salary

totalSalary = totalSalary + salary

count = count + 1

DISPLAY “Enter employee name. (Enter * to quit.)”

READ name

END WHILE

//Calculate average salary with mix , max range

averageSalary = totalSalary / count

rangeMin = averageSalary - 5

rangeMax = averageSalary + 5

DISPLAY “The following employees have a salary within $5,000 of the mean salary of “ + averageSalary + “.”

For (x = 0; x < count; x++)

IF (employeeSalaries[x] >= rangeMin OR employeeSalaries[x] <= rangeMax )

DISPLAY employeeNames[x] + “\t” + employeeSalaries[x]

END IF

END FOR

END

See more about JAVA at brainly.com/question/12978370

#SPJ1

5 0

1 year ago