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My name is Ann [436]
2 years ago
11

If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa

d of 200N. Please answer fast
Physics
1 answer:
vladimir2022 [97]2 years ago
7 0

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

◆ E = 100N

This is a Right answer...

I hope you understand...

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6. Explain the causes of global warming and its side effects. [6]<br><br> Help me plssssss brainlest
nata0808 [166]

Answer:

Ongoing effects include rising sea levels due to thermal expansion and melting of glaciers and ice sheets, and warming of the ocean surface, leading to increased temperature stratification. Other possible effects include large-scale changes in ocean circulation

Explanation:

Please give me Brainliest

3 0
3 years ago
Match each type of wave to the way it moves.
OverLord2011 [107]

Answer:

Transverse wave- Back and forth at right angles to the direction of the wave arrow.

longitudinal wave- bask and forth in the direction of the motion of the motion of the wave.

electromagnetic wave- two alternating waves moving at right angles to each other.

Explanation:

In a longitudinal wave, the particles vibrate at right angles in reference to the wave motion.

In a transverse wave, the particles vibrate parallel to the wave motion

Electromagnetic waves occur as a result of the interaction between two  waves and are normally transverse in nature.  

8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

s_A = -6 + 9t

s_B = 5 - 8t

When A an B meets, they are at the same position and at the same time. So

s_A = s_B

-6 +9t = 5 - 8t

17t = 5 + 6 = 11

t = 11/17 = 0.647 s

s_A = -6 + 9*0.647 = -0.176 m

So where they meet is 0.176m from the flagpole, westward.

5 0
2 years ago
If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 N for a distance of 6
mel-nik [20]

The block's velocity is determined as 10.03 m/s.

<u>Explanation:</u>

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

\text {Force } \times \text { displacement }=\frac{1}{2} \times m \times v^{2}

Thus, the velocity can be determined as

\text {velocity}=\sqrt{\frac{2 \times \text {Force} \times \text {displacement}}{m}}

\text {velocity}=\sqrt{\frac{2 \times 3.7 \times 6.8}{0.50}}=\sqrt{\frac{50.32}{0.50}}=\sqrt{100.64}

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

5 0
3 years ago
A ball dropped from a bridge takes 3.0 seconds to reach the water below. How far is the bridge from the water?
Komok [63]
Since it is dropped, initial velocity u = 0

Using s = ut + (1/2)gt^2,        putting u = 0,  g = 10 m/s^2

s =(1/2)gt^2,                  t = 3s

s = 0.5 * 10 * 3 *3

s = 45 m.

The bridge is 45m above the water.
8 0
2 years ago
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