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prisoha [69]
3 years ago
15

I need help due today!!!!!

Chemistry
2 answers:
jarptica [38.1K]3 years ago
6 0

Answer:

A

Explanation:

Hitman42 [59]3 years ago
5 0

Answer:

A. 5 g/mL

Explanation:

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How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
3 years ago
The number of protons in an atom is called?
Serhud [2]
The thing that it is called is it is called the atomic number of the thing
3 0
3 years ago
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What are the chemical names for KF
den301095 [7]
Um, I think it’s: k is potassium and F is fluorine so potassium Fluoride
7 0
3 years ago
NH4 oxidation number
Lubov Fominskaja [6]
The answer is +1! Have a great day!
6 0
3 years ago
Ten pints of 15 % salt solution are mixed with 15 pints of 10 % salt solution. What is the
sergij07 [2.7K]
Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
\frac{15}{100}=\frac{m_1}{10}\ \ |*10\\
m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
ms=ms_1+ms_2=15+10=25pints\\m=m_1+m_2=1,5+1,5=3pints
\\\frac{m}{ms}*100\%=\frac{3}{25}*100\%=12\%
7 0
3 years ago
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