Answer 1) In the given reaction of sulfuric acid


On addition of nitrogen monoxide gas the reaction rate increases and more amount of product is formed.
So, it is clear that NO is the catalyst in this reaction.
Answer 2) This can be proven that NO is catalyst because it increases the rate of the reaction, but it is not consumed during the reaction, and it also gets regenerated at the end of reaction.
Hence, nitrogen mono oxide is considered as the catalyst in the given reaction.
Answer 3) It increases the rate of reaction by decreasing the activation energy of the reaction. Also it can be clearly seen in this reaction the NO is reacting with oxygen to lower the energy of activation. So, it is providing an alternative pathway for proceeding the reaction. This all confirms the assumptions of NO being the catalyst.

Answer: The correct option is B.
Explanation: There are 2 regions of the solar system.
1) Inner region: There are 4 planets which lie in this region: Mercury, Venus, Earth and Mars. The inner region planets are rocky in nature. The orbit time of these planets around the sun is short. They have 0, 1 or 2 satellites in total. There is no ring system in these planets.
2) Outer region: There are 4 planets which lie in this region: Jupiter, Saturn, Uranus and Neptune. The outer region planets are gaseous in nature. The orbit time of these planets around the sun is long. They have usually more number of satellites around them. Ring system in these planets is very common.
Hence, Mars resides in the inner region of the solar system because it has a rocky surface that one could firmly stand on.
7 is atomic symbol 9 is atomic density 8 is the atomic number
Answer:
all 4 of the middle ones are part of the nucleus
When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C.
<span>The answer is - 6.30 * 10^3 kJ/mol
</span>