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Arisa [49]
3 years ago
8

People who make goods and services are called _____ .

Chemistry
2 answers:
Yuri [45]3 years ago
8 0
B producers. Think of it as if they’re producing the goods
Oxana [17]3 years ago
7 0
I think that the answer is b
You might be interested in
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
Choose all the answers that apply.
Anni [7]

Answer:

I believe it's the lowest portion of the atmosphere

3 0
2 years ago
If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?
Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

\tt \dfrac{5000~g}{46~g/mol}=108.7~moles

moles of glucose to produce 108.7 moles ethanol :

\tt \dfrac{1}{2}\times 108.7=54.35

54.35 moles = 5 hours

moles of 1000 kg of glucose :

\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles

So for 5555.5 moles, it takes :

\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days

7 0
3 years ago
Of the following: H2(g); He(g); CO2(g); which would behave least like an ideal gas? Why?
Margarita [4]
Answer:

CO2(g)

Because CO2 is the larges molecule with specific geometric, therefore it is not likely to behave as an ideal gas.
4 0
3 years ago
After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
FromTheMoon [43]

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

<em></em>

I hope it helps!

5 0
2 years ago
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