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MaRussiya [10]
3 years ago
13

How do scientists think that gravity affected the formation of our solar system?

Chemistry
1 answer:
Makovka662 [10]3 years ago
5 0
Maybe because gravity has control of each formation of the solarsydtem thats why its just a guess
You might be interested in
If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass
Luden [163]

The percentages of KBr and KI  in the sample by mass is 80.68 and 19.32 % respectively.

<h3>What is Molar Mass ?</h3>

Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

Molecular weight of Br = 79.9

Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

K will be 0.3289 x

and let the mass of KI present be y

K will be 0.235y

x +y =5.76

0.3289x+0.235y = 1.79

0.0939y = 0.1045

y = 1.1125 gm

x = 5.76-1.1125

x = 4.6475 gm

% of KBr = (4.6475/5.76  )*100 = 80.68 %

% of KI = (1.1125/5.76) *100 = 19.32%

To know more about Molar Mass

brainly.com/question/12127540

#SPJ1

8 0
2 years ago
what volume of 1.75 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3 ?
Evgesh-ka [11]

The balance chemical equation is :

2HCL + Na2CO3 -----> 2NaCl + H2O + CO2

According to Question,

Given,

Molarity of HCL = 1.75 m

Sodium Carbonate (Na2CO3) = 0.100 m

For finding out the molarity,

c = n solute / Vsolution  => n = c.Vsolution

nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3

0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3

= 0.150 moles of  H3O^+

As we have already know the molarity of HCL , we easily calculate what volumes by many moles.

c = nsolute / Vsolution => Vsolution = nsolute / c

VH3O^+ = 0.150 moles / 1.75 mol L^-1 =  0.0857 L

To know more about Molarity here :

brainly.com/question/8732513?referrer=searchResults

#SPJ4

6 0
1 year ago
Toluene is one of the components of crude oil which shows the balanced combustion reaction for toluene
satela [25.4K]
Toluene is aromatic organic compound and is derived from benzene by substituting on H with methyl group. The molecular formula of Toluene is C₇H₈.
When Toluene is subjected to combustion reaction it produces carbon dioxide and water. The balance chemical reaction for combustion of toluene is as follow,

                               C₇H₈  +  9 O₂   →   7 CO₂  +  4 H₂O
4 0
3 years ago
As the solar oven operate, what happens to the kinetic energy of the particles of matter in the air and the food inside
umka2103 [35]

Answer:

The average kinetic energy of the particles of matter in the air and the food inside increases

Explanation:

The relationship between the average Kinetic energy and temperature is given by the following formula

K = 3×R×T/(2×N_A)

Where;

R = The universal gas constant = 8.314 J/(mol·K)

N_A = Avogadro's number = 6.02 × 10²³ atoms/mol

T = The temperature of the gases in Kelvin

Given that a solar oven is able to raise the temperature to about 200°F, food cooks slower than in a conventional oven

However, given that the temperature and the average kinetic energy are directly related, the average kinetic energy rises.

6 0
3 years ago
What is the molarity of a 10.5 %% by mass glucose (C6H12O6C6H12O6) solution? (The density of the solution is 1.03 g/mLg/mL .) Ex
Kay [80]

Answer:

Molarity = 54.50 M

Explanation:

Molarity is defined as the number of moles of a solute in 1 liter of solution. It has mol/l unit.

Molar mass of glucose, C6H12O6 = (6*12) + (1*12) + (16*6)

= 72 + 12 + 96 = 180g/mol

Density of glucose solution = 1.03g/ml

Density in g/l = 1.03g/ml * 1ml/10^-3l

= 1030g/l

10.5% mass of glucose = 10.5/100 * 180

= 18.9g/mol

Molarity = density (g/l)/molar mass (g/mol)

= 1030/18.9

= 54.50 M

6 0
2 years ago
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