Answer:
The answer to your question is below
Explanation:
a) HCl 0.01 M
pH = -log [0.01]
pH = - (-2)
pH = 2
b) HCl = 0.001 M
pH = -log[0.001]
pH = -(-3)
pH = 3
c) HCl = 0.00001 M
pH = -log[0.00001]
pH = - (-5)
pH = 5
d) Distilled water
pH = 7.0
e) NaOH = 0.00001 M
pOH = -log [0.00001]
pOH = -(-5)
pH = 14 - 5
pH = 9
f) NaOH = 0.001 M
pOH =- log [0.001]
pOH = 3
pH = 14 - 3
pH = 11
g) NaOH = 0.1 M
pOH = -log[0.1]
pOH = 1
pH = 14 - 1
pH = 13
Answer:
105.8 g of Na would be required
Explanation:
Let's think the reaction:
2Na(s) + Cl₂(g) → 2NaCl (s)
1 mol of chlorine reacts with 2 moles of sodium
Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles
Let's determine the mass of them.
4.6 mol . 23 g/mol = 105.8 g
Answer:
The answer is <u>applied research</u>
Explanation:
Pure research becomes <u>applied research</u> when scientists develop a hypothesis based on the data and try to solve a specific problem.
This is because the pure research try to understand, predict or explain the behavior of different phenomena <em>(the data)</em> while the applied research try to develop new technologies or methods (<em>hypothesis)</em> to take part, intervene and/or create changes on these phenomena and solve a <em>specific problem.</em>
Are produced 72 grams of water in this reaction.
<h3>Mole calculation</h3>
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:



So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O


Finally, just find the number of grams of water using your molar mass:


So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237