Answer:
18 years, 4 months and 10 days.
Step-by-step explanation:
Given that the person invests $ 1000 in an account with compound interest each month, with an interest rate of 6%, to determine how long the investment must maintain to reach $ 3,000, the following calculation must be performed:
3,000 = 1,000 (1 + 0.06 / 12) ^ Yx12
3,000 = 1,000 (1 + 0.06 / 12) ^ 18.36x12
3,000 = 3,000
Therefore, the person must keep his investment for a period of 18.36 years. Since 12 x 0.36 is equal to 4.32, the total investment time should be 18 years, 4 months and 10 days.
Answer: No, No, Yes, Yes, Yes
<u>Step-by-step explanation:</u>
At 2:15 the temperature is 7°
It decreases 3° every 15 minutes ⇒ -3
Here is a table:
time | temperature
2:15 | 7
2:30 | 7 - 3 = 4
2:45 | 7 - 3 - 3 = 1
3:00 | 7 - 3 - 3 - 3 = -2
3:15 | 7 - 3 - 3 - 3 - 3 = -5
3:30 | 7 - 3 - 3 - 3 - 3 - 3 = -8
Do you see a pattern? This can be written as:
7 + (-3) + (-3) + (-3) + (-3) + (-3) + (-3)
7 - (3)(5)
7 + 5(-3)
we are given that
8 more than a number is greater than or equal to 0
Let's assume that number as 'x'
8 more than a number is
now, it is greater than or equal to 0
so, we can write as
now, we can solve for x
Subtract both sides 8
...............Answer
Step-by-step explanation:
<u>Properties used</u>
- logₐ a = 1
- log aᵇ = b log a
- log ab = log a + log b
See the steps below
- - log (4*10⁻³) =
- - (log 4 + log 10⁻³) = (log 4 ≈ 0.6 rounded)
- - (0.6 - 3*log 10) =
- - (0.6 - 3*1) =
- - (0.6 - 3) =
- - (- 2.4) =
- 2.4
