Answer:
Presence of water molecules
Explanation:
Temperature decreases with an increase in altitude. At sufficiently high altitudes, the air is much colder than the air on the surface of the Earth. Water vapor has a low density and is capable to rise until it gets into a medium with a significantly low temperature and pressure to condense and produce water droplets out of water vapor. Those droplets then form clouds.
The amount left over after T years where P is initial amount is
it halves each time so after t times of the 5000 years have elapsed, the amount is now (1/2)^t of the original amount
find how many half lives
10000/5000=2
(1/2)^2=1/4
1/4 of original amount after 10000 years
after 50000 years
50000/5000=10
(1/2)^10=1/1024
1/1024 of original amount after 50000 years
it dissapears when it attains an amount you deem is nigligible, so if you had 1 mol of subsutance, you might say it dissapears when it gets to 10^-23 or about 6.02 molecules
cytoplasm
cell membrane
nucleus (unless bacteria)
DNA
mitochondria (unless root hair cell)
The mass of carbon in 1 liter of mixture = 1.108 g
<h3>What is the mass of carbon in 1 liter of the mixture?</h3>
The mass of carbon in 1 liter of the mixture is determined as follows:
First the moles of gas is determined using the ideal gas formula:
n = (1 * 1)/(0.08205L * 298)
n = 0.0409 mole of total gas
mass of gas is then determined using the formula:
mass = 1 * 1.375
mass = 1.375 g
Let x = mass of CH₄ and y = mass of C₄H₁₀
x + y = 1.375 g
nCH₄ + nC₄H₁₀ = ntotat
moles = mass/molar mass
x + y = 1.695 => y = 1.695 - x
(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409
x/16 + (1.375 - x)/58 = 0.0409
x = 0.380 g CH₄
y = 1.375 - 0.380
y = 0.995 g of C₄H₁₀
mass of C in CH₄ = 12/16 * 0.380 = 0.285
mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823
Mass of carbon in 1 liter of mixture = 0.285 + 0.823
Mass of carbon in 1 liter of mixture = 1.108 g
In conclusion, the carbon is the major component in the mixture.
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Answer:
The answer to your question is 8.21 g of H₂O
Explanation:
Data
mas of water = ?
mass of hydrogen = 4.6 g
mass of oxygen = 7.3 g
Balanced chemical reaction
2H₂ + O₂ ⇒ 2H₂O
Process
1.- Calculate the atomic mass of the reactants
Hydrogen = 4 x 1 = 4 g
Oxygen = 16 x 2 = 32 g
2.- Calculate the limiting reactant
Theoretical yield = H₂/O₂ = 4 / 32 = 0.125
Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630
From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.
3.- Calculate the mass of water
32 g of O₂ ---------------- 36 g of water
7.3 g of O₂ --------------- x
x = (7.3 x 36) / 32
x = 262.8 / 32
x = 8.21 g of H₂O
