Ca3(PO4)2 + 3H2SO4 3CaSO4 + 2H3PO4.
1 answer:
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Answer:
The heat of combustion is -25 kJ/g = -2700 kJ/mol.
Explanation:
According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.
Qcomb + Qcal = 0
Qcomb = - Qcal
The heat absorbed by the calorimeter can be calculated with the following expression.
Qcal = C × ΔT
where,
C is the heat capacity of the calorimeter
ΔT is the change in temperature
Then,
Qcomb = - Qcal
Qcomb = - C × ΔT
Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ
Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:
The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:
Answer: The correct answer is option(A).
Explanation:
Total forces exerting on the car = F
= Force on car exerting in right direction
= Force on car exerting in left direction
= Force on car exerting in upward direction
= Force on car exerting in downward direction
(negative sign shows the direction)
Since, upward force are equal in magnitude but opposite in direction by which they will balance out each other.so, the net force car will be due to two forces and
(negative shows the direction)
The magnitude (size) and direction of the cumulative force acting on the car will 30 N towards right direction.Hence, correct answer is option(A).