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2 years ago

Ca3(PO4)2 + 3H2SO4  3CaSO4 + 2H3PO4.

Chemistry

1 answer:

Dominik [7]2 years ago

4 0

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Electrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of

Aleonysh [2.5K]

Answer:

CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode

Explanation:

The valence of the elements in this case is as follows -

Cu - 2e-

Sn - 4e-

Cr - 3e-

CuSO4 cell will have the greatest amount of deposit among all three

The atoms of copper metal will deposit at the cathode. At the cathode, the least number of moles of electrons needed .

Hence, more amount of copper can be extracted out by the electrolyte

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3 years ago

3. How much power is required to pull a sled if you use 60j of work in secound?

JulijaS [17]

Answer:

The answer is 60W

Power = Work done/ time

time = 1 second

Work done = 60J

Power = 60/1

= 60W

Hope this helps.

3 0

2 years ago

Which general equation shows a Single-displacement reaction?

Stella [2.4K]

Hello! The answer is D

A good note for these is when there are three elements, one being a singular element and another a compound and there’s a single switch, this could show a single-displacement

Have a good day gamer.

6 0

1 year ago

What would the hydroxide ion concentration be if the hydrogen ion concentration was 1 x 10-3 M?

Sonbull [250]

Answer:

1 x 10⁻¹¹ M

Explanation:

(Step 1)

Determine the pH.

pH = -log[H⁺]

pH = -log[1 x 10⁻³ M]

pH = 3

(Step 2)

Determine the pOH.

pH + pOH = 14

3 + pOH = 14

pOH = 11

(Step 3)

Determine the hydroxide (OH⁻) concentration.

[OH⁻] = 10^-pOH

[OH⁻] = 10⁻¹¹

[OH⁻] = 1 x 10⁻¹¹ M

3 0

1 year ago

The pH of a 0.29 M solution of carbonic acid (H2CO3) is measured to be 3.44. Calculate the acid dissociation constant Ka of carb

arsen [322]

Answer: 4.55x10^-7

Explanation:

H2CO3 + H20 <==> H3O+ + HCO3-

Desigining an ICE table, we have:

Initial conc. of H2CO3 = 0.29 M

Initial conc. of H3O+ = 0

Initial conc. of HCO3- = 0

Change in conc. of H2CO3 = - x

Change in conc. of H3O+ = x

Change in conc. of HCO3- = x

Equilibrium conc. of H2CO3 = 0.29 - x

Equilibrium conc. of H3O+ = x

Equilibrium conc. of HCO3- = x

but pH = 3.44

pH = - log[H30+]

[H30+] = 10^-3.44 = 3.63x10^-4

[H30+] = 3.63x10^-4

Ka = [H3O+].[HCO3-] / [H2CO3]

[H30+] = x = 3.63x10^-4

[HCO3-] = 3.63x10^-4

[H2CO3] = 0.29 - x = 0.29 - 3.63x10^-4 = 0.289637

Ka = (3.63x10^-4)(3.63x10^-4)/0.289637 = 4.55x10^-7

6 0

3 years ago