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antiseptic1488 [7]
3 years ago
15

The process by which particles in a solution spread out evenly is called?

Chemistry
1 answer:
padilas [110]3 years ago
7 0

Answer:

this is your answer.....

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Fruit salad is an example of what?
gulaghasi [49]
I think the answer will be homogeneous mixture
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What is the Chemical Composition of the Element of Mercury in the <br> Periodic Table of Elements?
charle [14.2K]
Hg<span> is the modern </span>chemical symbol for mercury<span>. It comes from hydrargyrum, a Latinized form of the Greek word ὑδράργυρος (hydrargyros), which is a </span>compound<span>word meaning "water-silver" (from ὑδρ- hydr-, the root of ὕδωρ, "water," and ἄργυρος argyros "silver") – since it is liquid like water and shiny like silver.</span>
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3 years ago
Which chemical equation is balanced to show that mass is conserved during the reaction? *
Mazyrski [523]

Answer:

B  

Step-by-step explanation:

Equation B is balanced. It has four atoms of H and four of O on each side of the reaction.

A is <em>wrong</em>. It has two atoms of Cl on the left and only one on the right.

C is <em>wrong</em>. It has two atoms of O on the left and four on the right.

D is <em>wrong</em>. It has two atoms of Cl on the left and only one on the right.

3 0
3 years ago
Soluble or Insoluble in water: Dirt
Varvara68 [4.7K]

Answer:

Insoluble

Explanation:

Like other non-polar molecules such as petrol, wax and grease, most food and dirt is not soluble in water.

https://www.primaryconnections.org.au/sites/all/modules/primaryconnections/includes/SBR/data/Chem/sub/soap/soap.htm#:~:targetText=Like%20other%20non%2Dpolar%20molecules,is%20not%20soluble%20in%20water.

5 0
4 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
3 years ago
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