Answer:
−
12 , −
6
, −
4
, −
3, −2, −1, 1, 2, 3, 4, 6
, 12
Step-by-step explanation:
-12 * 1 = -12
-6 * 2 = -12
-4 * 3 = -12
-3 * 4 = -12
-2 * 6 = -12
-1 * 12 = -12
1 * -12 = -12
2 * -6 = -12
3 * -4 = -12
4 * -3 = -12
6 * -2 = -12
12 * -1 = -12
Answer: The equations are 5t + e = 725 and 3t + e = 505
Step-by-step explanation: We shall start by assigning letters to the unknown variables, hence we shall call the treadmill t, and we shall call the elliptical machine e.
If on Saturday, she ran 5 miles on the treadmill and 1 mile on the elliptical machine and she burned 725 calories in the process, we can express this as
5t + e = 725 ------(1)
Also on Sunday, she ran 3 miles on the treadmill and 1 mile on the elliptical machine and burned 505 calories in the process, that too can be expressed as
3t + e = 505 ------(2)
We now have a pair of simultaneous equations which an be solved by the elimination method (reason being that on of the unknowns have the same coefficient, that is variable e).
Subtract equation (2) from equation (1) and you arrive at;
2t = 220
Divide both sides of the equation by 2
t = 110
Having calculated the value of t, substitute for the value of t into equation (1)
5t + e = 725
5(110) + e = 725
550 + e = 725
Subtract 550 from both sides of the equation
e = 175
The above calculations shows that the calories burned on each gym equipment are;
Treadmill = 110 per hour
Elliptical = 175 per hour
The answer is 20 pt. Hope this helped
<h3>
Answer: (c * d)(x) =
4x^3 + 18x^2 - 10x</h3>
Work Shown:
I'm assuming the dot means multiplication. If so, then,
(c * d)(x) = c(x)*d(x)
(c * d)(x) = [ c(x) ] * [ d(x) ]
(c * d)(x) = (4x-2)(x^2+5x) .... substitution
(c * d)(x) = 4x(x^2+5x) - 2(x^2+5x) ... distribute
(c * d)(x) = 4x(x^2)+4x(5x) - 2(x^2)-2(5x) ... distribute again
(c * d)(x) = 4x^3 + 20x^2 - 2x^2 - 10x
(c * d)(x) = 4x^3 + 18x^2 - 10x
Answer:
310%
Step-by-step explanation:
310% can be expressed as a mixed number because 150% would be 1 1/2.
310% would be 3 1/10.
