We are given the following conditions:

Since we are told it slows down at a constant rate, we know we are dealing with uniformed accelerated motion, or UAM for short.
So we look at our kinematics equation that contains the given variables.

This contains our target variable and our initial conditions. Plug and chug, we get:

Thus the answer is:
a = -7m/s^2
Hope this helps!
Explanation:
a) Hammer hits a nail
Action: Hammer hitting the nail
Reaction: Nail Hitting the hammer.
B) . Earth's gravity pulls down on a book.
Action: Earth pull downward on the book.
Reaction: The Book pull's the Earth Upward.
C) A helicopter blade pushes air downward.
Action: Blade push air downward
Reaction: The force in pushes the helicopter upward.
Answer:
0.435atm
Explanation:
cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air with a volume of 0.185 m3 at a pressure of 0.740 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.315 m3. If the temperature remains constant, what is the final value of the pressure?
Given
Initial pressure P1= 0.740atm
Initial volume V1= 0.185 m3
Final pressure P2= ?
Final volume V2= 0.315 m3
At constant temperature, the pressure of a syste is inversely proportional to volume, by Boyles law then
P1V1=P2V2
P2=P1V1/V2
=(0.185*0.740)/0.315
0.1369/0.315
= 0.435atm
Therefore, final pressure is 0.435atm
They compress or expand depending on amount of pressure or depending on the temperature