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tatyana61 [14]
2 years ago
8

A hiker travels 12 km in a direction of 50 degrees west of north. What are the north and west components of this displacement?

Physics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

The north and west components of this displacement are 9.19 km and -7.71 km respectively.

<h3>North component of the displacement</h3>

The north component of the displacement is calculated as follows;

Dy = D sinθ

Dy = 12 km x sin50

Dy = 9.19 km

<h3>West component of the displacement</h3>

Dx = D x cosθ

Dx = - 12 km x cos(50)

Dx = -7.71 km

Learn more about components of displacement here: brainly.com/question/13416288

#SPJ1

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7 0
3 years ago
A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c
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Answer:

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Part b)

a_{cart} = \frac{T}{M}

Part c)

a = \frac{mg}{M + m}

Part d)

a = 1.35 m/s^2

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

mg - T = ma

so we have

a_{hanger} = g - \frac{T}{m}

Part b)

now for car that is rolling on the floor the net force is given as

F = Ma

T = Ma

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Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

T = Ma

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a = \frac{mg}{M + m}

Part d)

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M = 2.40 kg

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so we will have

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6 0
3 years ago
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