The gas molecules bump into each other more frequently. The gas could turn into a liquid if it is also combined with a lowered temperature.<span />
the missing blank is filled by 11 O2
that is
= 2C4H6 + 11O2 = 8 CO2 + 6H2O
C4H6 reacted with oxygen (O2 )through the process of combustion to form carbon iv oxide (CO2) and water (H2O) . 11 infront of O2 is to make sure the molecules of O2 is balanced in both reactant side and the product side
Answer:
Mole fraction of solute (heptane) → 0.73
Explanation:
Mole fraction = Moles of solute or solvent / Total moles
Let's calculate the moles of everything:
Moles of solute → Mass of solute / Molar mass
36 g / 100 g/mol = 0.36 moles
Moles of solvent → Mass of solvent / Molar mass
16 g / 119.35 g/mol = 0.134 moles
Total moles = 0.36 + 0.134 = 0.494 moles
Mole fraction of solute = 0.36 / 0.494 → 0.73
I think the correct answer from the choices listed above is the first option. The statement that is true would be that compounds that can form more hydrogen bonds are more soluble in water. Hope this answers the question. Have a nice day.
Answer:
No, it is not feasible because the Gibbs free energy change is positive
Explanation:
∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol
∆Sreaction = (42 + 27) J/Kmol - (33 + 44) J/K = -8J/Kmol
From;
∆G = ∆H - T∆S
∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]
∆G = 2.57 × 10^5 J/mol
Note that when the change in free energy is positive, a reaction is non spontaneous. Only a reaction that has a negative change in free energy is spontaneous.
