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3 years ago

A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?

Chemistry

1 answer:

ololo11 [35]3 years ago

6 0

Answer:

n= 0.03 moles

Explanation:

Using the ideal gas law:

PV=nRT

nRT=PV

n= PV/RT

n: moles

P: pressure in atm

V= volume in L

R= Avogadro's constant = 0.0821

T= Temperature in K => ºC+273.15

n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)

n= 0.03 moles

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a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc

ladessa [460]

Answer:

The molarity of the solution is 1.1 $\frac{moles}{liter}$

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case

number of moles of solute= 0.564 moles
volume= 0.510 L

Replacing:

$molarity=\frac{0.564 moles}{0.510 L}$

Solving:

molarity= 1.1 $\frac{moles}{liter}$

The molarity of the solution is 1.1 $\frac{moles}{liter}$

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