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Viefleur [7K]
3 years ago
15

Newton's Laws

Physics
1 answer:
Sergio [31]3 years ago
3 0

Answer:They are equal and act in opposite directions.

Explanation:Newton's third law of motion states that for every action there is an equal and opposite reaction. In the case of Bode's rocket, the pressurized air in the bottle forces the water to gush downward out of the bottle, causing the rocket to launch upward into the air. The force of the water gushing downward is equal to the upward force on the rocket. So, the two forces are equal and act in opposite directions.

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A vertical spring with spring stiffness constant 305 N/m oscillates with an amplitude of 28.0 cm when 0.235 kg hangs from it. Th
den301095 [7]

Answer:

The function that describe the motion in the time

y (t) = 0.28m * sin ( 36.025 * t)

Explanation:

The angular frequency of oscillation of the spring

w = √k/m

w = √305 N/m / 0.235 kg

w = 36.025 rad / s

To determine the function of the motion knowing as a motion oscillation in a amplitude a frequency

y(t) = A * sin (w t )

So

A = 28.0 cm * 1 m / 100 cm = 0.28 m

So replacing to determine the function of the motion in the time

y (t) = A sin (w t)

y (t) = 0.28m * sin ( 36.025 * t)

7 0
3 years ago
A circular disk, a ring, and a square (is hollow) have the same mass M and width 2r. For the moment of inertia about their cente
andre [41]

Answer:

d is your answer

Explanation:

4 0
4 years ago
A proton moves with a speed of 4.00 106 m/s horizontally, at a right angle to a magnetic field. What magnetic field strength is
Free_Kalibri [48]

Answer:

Magnetic field, B=2.55\times 10^{-14}\ T

Explanation:

It is given that,

Speed of proton, v=4\times 10^6\ m/s

Mass of the proton, m=1.67\times 10^{-27}\ kg

Charge on proton, q=1.6\times 10^{-19}\ C

We need to find the magnetic field strength required to just balance the weight of the proton and keep it moving horizontally.

The Lorentz force is given by :

F=q(v\times B)=qvB\ sin90.............(1)

The weight of proton,

W=mg..............(2)

From equation (1) and (2), we get :

mg=qvB

B=\dfrac{mg}{qv}

B=\dfrac{1.67\times 10^{-27}\ kg\times 9.8\ m/s^2}{1.6\times 10^{-19}\ C\times 4\times 10^6\ m/s}

B=2.55\times 10^{-14}\ T

Hence, this is the required solution.

3 0
3 years ago
Assume it takes 8.00 min to fill a 50.0-gal gasoline tank. (1 U.S. gal = 231 in.3) (a) Calculate the rate at which the tank is f
vagabundo [1.1K]

The volumetric rate or flow rate of a fluid is defined as the amount of the volume of a fluid circulating on a surface per unit of time. In this case we have units given initially: Gallons and minutes. For the first part we will convert the minutes to seconds, and we will obtain the flow rate under that measure. For the second case we will convert the gallons to cubic meters and obtain the desired value. Recall the following conversion rates,

1 min = 60s

1 U.S Gal = 0.00378541178 m^3

If the flow rate is defined as the volume by time, the flow rate with the given values is

Q = \frac{V}{t}

Q = \frac{50Gal}{8min}

Q = 6.25 Gal/min

PART A ) Converting to Gal/seconds, we have,

Q = 6.25 \frac{Gal}{min}(\frac{1min}{60s})

Q = 0.10416Gal/s

PART B) Converting Gal/seconds to m^3/s

Q = 0.104116\frac{Gal}{s} (\frac{0.00378541178 m^3}{1 Gal})

Q = 3.941*10^{-4}m^3/s

4 0
3 years ago
A rock slides down from A to B along the inside surface of a frictionless hemispherical bowl. As the rock slides, mechanical ene
DIA [1.3K]

Answer:

the normal force on the rock acts perpendicular to the bowl's surface.

Explanation:

As we know that Normal force is the reaction force of two contact surfaces which always act perpendicular to the contact surfaces

Here we know that the rock is moving inside the bowl

So Normal force on the rock must perpendicular to the surface of the bowl which always passes through the center of the bowl.

Since the rock is moving in vertical plane so it must have two acceleration

1) Tangential acceleration which will increase the magnitude of the speed along the tangential path

2) Centripetal acceleration which will change the direction of the rock

So here only correct option will be

the normal force on the rock acts perpendicular to the bowl's surface.

6 0
3 years ago
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