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3 years ago

Haha jk thats really funny that it doesnt let you take down questions

Physics

2 answers:

faltersainse [42]3 years ago

6 0

Answer:

Just commenting so I can get points.

Explanation:

beks73 [17]3 years ago

5 0

I wish i could take down questions

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A skier is traveling fast down a mountain slope. The table shows data

melisa1 [442]

Answer:

The pushing force and the skier's mass

(A) is correct option.

Explanation:

Given that,

Mass = 64 kg

Weight = 608 N

Velocity = 21 m/s

Forward force = 45 N

We need to calculate the reaction force of the snow pushing on the skier

Using given data,

The reaction force of the snow pushing on the skier is equal to the pushing force and the skier's mass.

Hence, The pushing force and the skier's mass

(A) is correct option.

6 0

3 years ago

A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl

Hunter-Best [27]

The ideal spring equation is

   Stretch = K times Force .

This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by π or
any other number, you multiply the stretch by the same number.

So you can always write a proportion for a spring:

   Stretch₁ / Force₁ = Stretch₂ / Force₂ .

Part A:

In Part-A of this question, the force is increased to (2.5 / 2.0) = 1.25 times .

So the stretch is also increased to 1.25 times .

   (1.25) x (6.1 cm) = 7.625 cm .

6 0

4 years ago

If a plane can travel 450 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the plane with

BabaBlast [244]

The speed of the plane through the air is 430 mph, and you described a day when the wind was blowing at 20 mph.

8 0

4 years ago

Read 2 more answers

A tank whose bottom is a mirror is filled with water to a depth of 19.6 cm. A small fish floats motionless a distance of 6.40 cm

ANEK [815]

Answer:

A. 4.82 cm

B. 24.66 cm

Explanation:

The depth of water = 19.6 cm

Distance of fish = 6.40 cm

Index of refraction of water = 1.33

(A). Now use the below formula to compute the apparent depth.

$d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\= \frac{1}{1.33} \times 6.40 \\= 4.82 cm.$

(B). the depth of the fish in the mirror.

$d_{real} = 19.6 cm + (19.6 cm – 6.40 cm) = 32.8 cm$

Now find the depth of reflection of the fish in the bottom of the tank.

$d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\d_{app} = \frac{1}{1.33} \times 32.8 = 24.66\\$

4 0

3 years ago

A small steel wire of diameter 1.0mm is connected to an oscillator and is under a tension of 5.7N . The frequency of the oscilla

kotegsom [21]

Answer:

The power output of the oscillator is 0.350 watt.

Explanation:

Given that,

Diameter = 1.0 mm

Tension = 5.7 N

Frequency = 57.0 Hz

Amplitude = 0.54 cm

We need to calculate the power output of the oscillator

Using formula of the power

$P=\dfrac{1}{2}\times\mu\times\omega^2\times a^2\times v$

Put the value into the formula

$P=\dfrac{1}{2}\times A\times\rho\times\omega^2\times a^2\times\dfrac{\sqrt{T}}{\mu}$

$P=\dfrac{1}{2}\times3.14\times(0.0005)^2\times7850\times(2\times\pi\times57.0)^2\times(0.54\times10^{-2})^2\times\sqrt{\dfrac{5.7}{3.14\times(0.0005)^2\times7850}}$

$P=0.350\ Watt$

Hence, The power output of the oscillator is 0.350 watt.

3 0

3 years ago