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Agata [3.3K]
3 years ago
13

The Hubble Space Telescope is an optical imaging telescope with extremely good angular resolution. Someone discovers an object t

hat Hubble cannot see at all. How might they have found it?
Engineering
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

<h2><em><u>Through</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>use</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>Hubble</u></em><em><u> </u></em><em><u>Space</u></em><em><u> </u></em><em><u>Telescope</u></em><em><u> </u></em><em><u>that's</u></em><em><u> </u></em><em><u>why</u></em><em><u> </u></em><em><u>they</u></em><em><u> </u></em><em><u>might</u></em><em><u> </u></em><em><u>find</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>enlarging</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>resolution</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>telescope</u></em><em><u>.</u></em></h2>

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Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part
ra1l [238]

Answer:

h1 = 290.16kj/kg

P = 1.2311

Prandil expression at 8

P=p1/p7×pr

=8(1.2311)

=9.85

Enthalpy state at 8 corresponding to 9.85

h1 = 526.13kj/kg

Now prandtl state at 9 that correspond to 1400k.

h9 = 1515.42kj/kg

Pr = 450.5

Prandtl expression at state 10

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Enthalpy at state 10 corresponding to prandtl 56.31

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4 0
3 years ago
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Strike441 [17]

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / 0.02^{0.22

K = 815.8165 Mpa

next, we determine the true strain

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given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

(εT) = 0.04481 mm

Now, we calculate the instantaneous length

l_i = l_0e^{ET

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we substitute

l_i =480mm × e^{0.04481

l_i =  501.998 mm

Now we find the elongation;

Elongation = l_i - l_0

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

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3 years ago
Which of the following describes the most direct and attainable way to reduce pollution in the environment?
kirill115 [55]

Answer:

i think its A. increasing research to find alternative natural resources for the future

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