Answer:
Step 1 of 3
Case A:
AISI 1018 CD steel,
Fillet radius at wall=0.1 in,
Diameter of bar
From table deterministic ASTM minimum tensile and yield strengths for some hot rolled and cold drawn steels for 1018 CD steel
Tensile strength
Yield strength
The cross section at A experiences maximum bending moment at wall and constant torsion throughout the length. Due to reasonably high length to diameter ratio transverse shear will be very small compared to bending and torsion.
At the critical stress elements on the top and bottom surfaces transverse shear is zero
Explanation:
See the next steps in the attached image
Answer:
Both of them are wrong
Explanation:
The two technicians have given the wrong information about the wires.
This is because firstly, a higher rating of AWG means it is smaller in diameter. Thus, the diameter of a 18 AWG wire is smaller than that of a 12 AWG wire and that makes the assertion of the technician wrong.
Also, the higher the resistance, the smaller the cross sectional area meaning the smaller the diameter. A wire with bigger cross sectional area will have a smaller resistance
So this practically makes the second technician wrong too
Answer:
strains for the respective cases are
0.287
0.318
0.127
and for the entire process 0.733
Explanation:
The formula for the true strain is given as:
Where
True strain
l= length of the member after deformation
original length of the member
<u>Now for the first case we have</u>
l= 1.6m
thus,
<u>similarly for the second case we have</u>
l= 2.2m
(as the length is changing from 1.6m in this case)
thus,
<u>Now for the third case</u>
l= 2.5m
thus,
<u>Now the true strain for the entire process</u>
l=2.5m
thus,
Scoot, Gordon, John, Gus, Wally, Alan, and Deke
Answer:
0.4 Dinas*s/cm^2
Explanation:
Tenemos una viscosidad:
V = 0.04 N*s/m^2
Y queremos reescribir esto en Dinas*s/cm^2
Primero transformemos la unidad del denominador, es decir, tenemos que pasar de 1/m^2 a 1/cm^2
Para ello, usamos que:
1m = 100cm
entonces:
(1m/100cm) = 1
Si elevamos ambos lados al cuadrado, obtenemos:
(1m/100cm)^2 = 1
Ahora podemos multiplicar el valor de la viscosidad por esto (que es igual a 1)
V = 0.04 N*s/m^2*((1m/100cm)^2 = 0.00004 N*s/cm^2
Ahora debemos convertir de Newtons a Dinas
Sabemos que:
1 N = 100,000 dinas
1 = (100,000 dinas/1N)
Entonces, de vuelta podemos multiplicar nuestra viscosidad por (100,000 dinas/1N), que es igual a 1 (asi que no cambia el valor, solo sirve para cambiar las unidades)
0.00004 N*s/cm^2 = (100,000 dinas/1N)*(0.00004 N*s/cm^2)
= (100,000 dinas)*(0.00004 s/cm^2)
= 0.4 Dinas*s/cm^2
