Answer:
Net efficiency of generating unit = 42.08 - 5 = 37.08 %
Explanation:
We have given that efficiency of the boiler = 91.2 % = 0.912
Carnot efficiency = 46.9 % = 0.469
Efficiency of generator = 98.4% =0.984
We have to find the efficiency of total generating unit
For finding the efficiency of total generating unit we have to multiply all the efficiencies
So efficiency of generating unit = 0.912×0.469×0.984 = 0.4208 = 42.08 %
For plant losses we have to subtract 5%
So net efficiency of generating unit = 42.08 - 5 = 37.08 %
Answer: 10.29 sec.
Explanation:
Neglecting drag and friction, and at road level , the energy developed during the time the car is accelerating, is equal to the change in kinetic energy.
If the car starts from rest, this means the following:
ΔK = 1/2 m*vf ²
As Power (by definition) is equal to Energy/Time= 75000 W= 75000 N.m/seg, in order to get time in seconds, we need to convert 100 km/h to m/sec first:
100 (Km/h)*( 1000m /1 Km)*(3600 sec/1 h)= 27,78 m/sec
Now, we calculate the change in energy:
ΔK= 1/2*2000 Kg. (27,78)² m²/sec²= 771,728 J
<h2>If P= ΔK/Δt, </h2><h2>Δt= ΔK/P= 771,728 J / 75,000 J/sec= 10.29 sec.</h2>
<h3><u>CSMA/CD Protocol:
</u></h3>
Carrier sensing can transmit the data at anytime only the condition is before sending the data sense carrier if the carrier is free then send the data.
But the problem is the standing at one end of channel, we can’t send the entire carrier. Because of this 2 stations can transmit the data (use the channel) at the same time resulting in collisions.
There are no acknowledgement to detect collisions, It's stations responsibility to detect whether its data is falling into collisions or not.
<u>Example:
</u>
, at time t = 10.00 AM, A starts, 10:59:59 AM B starts at time 11:00 AM collision starts.
12:00 AM A will see collisions
Pocket Size to detect the collision.
![\begin{aligned}&T_{t} \geq 2 T_{P}\\&\frac{L}{B} \geq 2 T_{P}\\&L \geq 2 \times T_{P} \times B\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26T_%7Bt%7D%20%5Cgeq%202%20T_%7BP%7D%5C%5C%26%5Cfrac%7BL%7D%7BB%7D%20%5Cgeq%202%20T_%7BP%7D%5C%5C%26L%20%5Cgeq%202%20%5Ctimes%20T_%7BP%7D%20%5Ctimes%20B%5Cend%7Baligned%7D)
CSMA/CD is widely used in Ethernet.
<u>Efficiency of CSMA/CD:</u>
- In the previous example we have seen that in worst case
time require to detect a collision.
- There could be many collisions may happen before a successful completion of transmission of a packet.
We are given number of collisions (contentions slots)=4.
Distance = 1km = 1000m
![\begin{aligned}&\text { Speed }=2 \times 10^{8} \mathrm{m} / \mathrm{sec}\\ &T_{P}=\frac{1000}{2 \times 10^{8}}=(0.5) \times 10^{-5}=5 \times 10^{-6}\\ &T_{t}=5 \mu \mathrm{sec}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26%5Ctext%20%7B%20Speed%20%7D%3D2%20%5Ctimes%2010%5E%7B8%7D%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bsec%7D%5C%5C%20%26T_%7BP%7D%3D%5Cfrac%7B1000%7D%7B2%20%5Ctimes%2010%5E%7B8%7D%7D%3D%280.5%29%20%5Ctimes%2010%5E%7B-5%7D%3D5%20%5Ctimes%2010%5E%7B-6%7D%5C%5C%20%26T_%7Bt%7D%3D5%20%5Cmu%20%5Cmathrm%7Bsec%7D%5Cend%7Baligned%7D)
Most minerals can be characterized and classified by their unique physical properties: hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.
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