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Svetach [21]
2 years ago
11

Why might there be multiple foremen on one work site?

Engineering
1 answer:
IrinaK [193]2 years ago
8 0

Answer:

4

Explanation:

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What are the rigging devices used to move loads such as steel plates and sheet piles without the use of slings, but grip the loa
scoundrel [369]

The rigging device which are used to move loads without the use of slings, but grip the load by biting down and using jaw tension to secure the load, is lifting clamps.

<h3>What are the rigging devices?</h3>

The rigging devices are used to lift the objects and items when the safety is required. This device is used in the industries.

Types of rigging devices

  • Rigging hooks-These rigging device is used when the heavy load need to be lift.
  • Lifting clamps-Lifting clamp are used to lift the device with jaw tension to secure the load. In this, there is no use of slings.
  • Pulley and blocks-In the load is lifts with the help of block and pulley arrangement. This is a widely used rigging device.

Thus, the rigging device which are used to move loads without the use of slings, but grip the load by biting down and using jaw tension to secure the load, is lifting clamps.

Learn more about the rigging devices here;

brainly.com/question/8430576

#SPJ1

4 0
2 years ago
After the load impedance has been transformed through the ideal transformer, its impedance is: + . Enter the real part in the fi
frozen [14]

Answer:

Ig =7.2 +j9.599

Explanation: Check the attachment

6 0
3 years ago
Five kg of water is contained in a piston-cylinder assembly, initially at 5 bar and 240°C. The water is slowly heated at constan
Digiron [165]

Answer:

The final temperature of water is 381.39  °C.

Explanation:

Given that

Mass of water = 5 kg

Heat transfer at constant pressure Q = 2960 KJ

Initial temperature = 240 °C

We know that heat transfer at constant pressure given as follows

Q=mC_p\Delta T

We know that for water

C_p=4.187\ \frac{KJ}{kg.K}

Lets take final temperature of water is T

So

Q=mC_p\Delta T

2960=5\times 4.187(T-240)

T=381.39  °C

So the final temperature of water is 381.39  °C.

7 0
2 years ago
What is the basic formula for actual mechanical advantage?
slavikrds [6]

Answer:

Mechanical Advantage Formula

The efficiency of a machine is equal to the ratio of its output to its input. It is also equal to the ratio of the actual and theoretical MAs. But, it does not mean that low-efficiency machines are of limited use. An automobile jack, for example, have to overcome a great deal of friction and therefore it has low efficiency. But still, it is extremely valuable because small effort can be applied to lift a great weight.

Also, in another way the mechanical advantage is the force generated by a machine to the force applied to it which is applied in assessing the performance of the machine.

The mechanical advantage formula is:

MA = FBFA

Explanation:

MAmechanical advantageFBthe force of the object

FAthe effort to overcome the force

3 0
3 years ago
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
ra1l [238]

Solution :

Given :

Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa

The phase diagram is provided below.

a). The phase is a standard mixture.

b). At pressure, p = 200 kPa, T = $T_{saturated}$

   Temperature = 120.21°C

c). Specific volume

  $v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$

  $v_x=v_f+x(v_g-v_f)$

       $=0.001061+0.7(0.88578-0.001061)$

       $=0.62036 \ m^3/kg$

d). Specific energy (u_x)

    $u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$

   $u_x=504.5 + 0.7(2024.6)$

         $=1921.72 \ kJ/kg$

e). Specific enthalpy $(h_x)$

   At $h_f = 504.71, \ \ h_{fg} = 2201.6$

   h_x=504.71+(0.7\times 2201.6)

        $= 2045.83 \ kJ/kg$

f). Enthalpy at m = 0.5 kg

  $H=mh_x$

       $= 0.5 \times 2045.83$

       = 1022.91 kJ

7 0
3 years ago
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