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lesantik [10]
3 years ago
8

A bronze bushing 60 mm in outer diameter and 40 mm in inner diameter is to be pressed into a hollow steel cylinder of 120-mm out

er diameter. Calculate the tangential stresses for steel and bronze at the boundary between the two parts
Engineering
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

The tangential stress for the steel at 30mm = 88.8MPa.

The tangential stress for the steel at 60mm = 35.5 MPa.

The tangential stress for the bronze at 20mm =  - 191.9 MPa.

The tangential stress for the bronze at 30mm =  - 138.6 MPa.

Explanation:

The outer radius bronze bushing = 60 mm/2 = 30 mm, the inner radius for bronze bushing = 40mm/2 = 20mm and the cylinder radius = 120mm/2 = 60mm.

Step one: The first step is to calculate or Determine the interface pressure.

The interface pressure = 0.05/ [ [ 30 × ( 1/210 ×10⁹) ] ×  [( 60² + 30²/ ( 60² - 30²) + 0.3 ] + [ 1/105 × 10⁹× [ ( 20² + 30²)/( 30² - 20²) - 0.3] ].

The interface pressure = 53.3 MPa

Step two: Determine the tangential stresses for steel and bronze as given below:

The tangential stress for the steel at 30mm = 10⁶ × 53.3 [ ( 0.06)² + (0.03)²/ ( 0.06)² - (0.03)² ] = 88.8 MPa.

The tangential stress for the steel at 60mm = 10⁶ × 53.3 × 2 × [0.03]²/  ( 0.06)² - (0.03)² ] = 35.5 MPa.

The tangential stresses for the bronze is calculated below;

=> The tangential stress for the bronze at 20mm = - [ 10⁶ × 53.3 × 2 × [0.03]² ] /  ( 0.03)² - (0.02)² ] = - 191.9 MPa.

The tangential stress for the bronze at 30mm = - [ 10⁶ × 53.3  × [ 0.03]² + (0.03)² ] /  ( 0.03)² - (0.02)² ] = - 138.6 MPa.

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2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es  

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Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

            ΔV = - E d

            E = - \frac{\Delta V}{d}

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

          E = - \frac{\Delta V}{d_1}  

Capacitor 2

         d₂ = 2 d₁  

         E₂ = - \frac{\Delta V}{2d_1}  

         E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor  

           Q = ε₀ \frac{A \Delta V}{d}  

Capacitor 1

           Q₁ = (ε₀ A ΔV) \frac{1}{d_1}

Capacitor 2

           Q₂ = (ε₀ A Δv) \frac{1}{2d_1}

           

            Q₂ = Q₁/2

       

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

         u_E  = ½ ε₀ E²  

calculamos para cada capacitor

           

Capacitor 1

         u_{E\  1} = ½ ε₀ E₁²

Capacitor 2

         u_{E 2} = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

     1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

    2) El capacitor con menor distancia tiene mayor carga

    3) El capacitor con menor distancia tiene mas densidad de carga  

Aprender mas aquí:  brainly.com/question/22813371

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