Answer: Option (c) is the correct answer.
Explanation:
Atomic number of sodium is 11 and its electronic configuration is 
. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.
: 
Atomic number of fluorine is 9 and its electronic configuration is 
. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.
:
Atomic number of aluminium is 13 and its electronic configuration is 
. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.
:
Thus, we can conclude that the listing for aluminum is correct.
Answer:
Option D. 1×10¯¹⁰ M
Explanation:
From the question given above, the following data were obtained:
pH = 10
Hydrogen ion concentration, [H+] =?
The hydrogen ion concentration, [H+] of the Ba(OH)2 solution can be obtained as follow:
pH = – Log [H+]
pH = 10
10 = – Log [H+]
Divide both side by – 1
– 10 = Log [H+]
Take the antilog of – 10
[H+] = antilog (– 10)
[H+] = 1×10¯¹⁰ M
Therefore, the hydrogen ion concentration, [H+] of the Ba(OH)2 solution is 1×10¯¹⁰ M
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A proton<span> is one of the most </span>important<span> types of subatomic particles. </span>Protons <span>combine with electrons and neutrons to </span>make<span> atoms. </span>Protons<span> are nearly the same size as neutrons and are much larger than electrons. ... </span>Protons<span> are composed of two up quarks and one down quark.......Hope this helps can you mark me brainliest?</span>
