B: nothing the color of the solution when heated
<h3><u>Answer</u>;</h3>
1.0875 x 10-2 atm
<h3><u>Explanation;</u></h3>
2O3(g) → 3O2(g)
rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t
The average rate of disappearance of ozone ... is found to
be 7.25 × 10–3 atm over a certain interval of time.
This means (ignoring time)
∆[O3]/∆t = -7.25 × 10^–3 atm
(it is disappearing, thus the negative sign)
rate = -(1/2)∆[O3]/∆t
rate = -(1/2)*(-7.25 × 10^–3 atm)
= 3.625 × 10^–3 atm
Now use the other part of the expression:
rate = +(1/3)∆[O2)∆t
3.625 × 10–3 atm = +(1/3)∆[O2)/t
∆[O2)/∆t = (3)*(3.625× 10^–3 atm)
= 1.0875 x 10-2 atm over the same time interval
Answer:
The volume of the gas sample at standard pressure is <u>819.5ml</u>
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.



1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,


Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

=735-42.2=692.8 mmhg
Now
By using combined gas law equation:



Here
are standard pressure and temperature respectively.
we have

Substituting value, we get


Answer: <span>A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called
<em>cis</em> Isomer.
Explanation: Geometric isomerism takes place about the double bond in alkenes when the alkyl groups are either situated at the same side (<em>
cis</em>) or are situated opposite (
<em>trans</em>) to each other.
Example: <em>
cis</em>
-2-Butene (highlighted red)
<em>
trans</em>
-2-Butene (highlighted blue)</span>
Answer:
b no
Explanation:
because it is decomposing into two elements