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zzz [600]
3 years ago
10

Indium has only two naturally occurring isotopes. the mass of indium-113 is 112.9041 amu and the mass of indium-115 is 114.9039

amu . part a use the atomic mass of indium to calculate the relative abundance of indium-113.
Chemistry
1 answer:
brilliants [131]3 years ago
8 0
The average atomic mass written in the periodic table is determined from the relative abundances of the element's isotopes. The equation would be:

Average Atomic Mass = ∑(Relative Abundance×Mass)

Let be the relative abundance of Indium-113. Because there are only 2 isotopes, their relative abundances should equal to 1, such that the relative abundance for Indium-15 is (1-x). The atomic mass of indium is 114.818 amu.

x(112.9041) + (1 - x)(<span>114.9039) = 114.818
Solving for x,
x = 0.043 or 4.3%</span>
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<h3>Answer:</h3>

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<h3>Explanation:</h3>

<u>We are given;</u>

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  • Volume of the solution is 270 ml

But, 1000 mL = 1 L

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We are required to calculate the molarity of the solution;

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Molarity = Moles ÷ Volume

In this case;

Molarity = 0.50 moles ÷ 0.27 L

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