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allsm [11]
3 years ago
6

PLEASE HELP ME YOU GUYSSS

Mathematics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

c i got it right on test

Step-by-step explanation:

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utorial Exercise A cylindrical tank with radius 4 m is being filled with water at a rate of 2 m3/min. How fast is the height of
SIZIF [17.4K]

Step-by-step explanation:

volume of a cylinder is

ground area × height = pi×r²×h

r = 4

what we need to calculate is how high the water stands with one "serving" of 2m³.

that height is then added every minute (with the additional 2m³ during that minute).

so,

2 = pi×4²×h = pi×16×h

2/16 = 1/8 = pi×h

h = (1/8) / pi = 1/(8pi) = 0.039788736... m

that is rounded about 0.04 m or 4 cm.

therefore, the water rises by 0.04 m or 4 cm per minute

0.04m/min

3 0
2 years ago
To improve his basketball skills, Troy decides to practice six times as many free throws and four times as many jump shots every
noname [10]
The answer is B. 6f+4j
6 0
3 years ago
Read 2 more answers
Solve for n.<br><br> n + 1 = 4(n – 8)<br> i will give a brainliest
yKpoI14uk [10]

n + 1 = 4(n - 8)

n + 1 = 4n - 32

n - 4n = -32 - 1

-3n = -33 / : (-3)

n = 11

6 0
3 years ago
What is the answer to 2 3/4 ÷ 1 5/8
alex41 [277]
Exact form:
22/13

Mixed number:
1 9/13
6 0
3 years ago
Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

4 0
1 year ago
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