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lukranit [14]
4 years ago
6

How are sedimentary rocks made?

Chemistry
1 answer:
Ad libitum [116K]4 years ago
3 0
Sedimentary rocks are formed when sediment is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension. This sediment is often formed when weathering and erosion break down a rock into loose material in a source area.

Hope i helped you :)
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Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-
Karolina [17]

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

  • 113.4 g ÷ 46 g/mol = 2.465 mol

Then we<u> use the PV=nRT formula</u>, where:

  • P = 1atm & T = 273K (This means STP)
  • n = 2.465 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

Input the data:

  • 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And <u>solve for V</u>:

  • V = 55.18 L
6 0
3 years ago
Will soapy water evaporate faster than water
love history [14]
The rate of evaporation would decrease because of
the formation of bonds between the soap and the water.
So, no. Regular water evaporates faster than soapy water
4 0
3 years ago
How to do my homework? i’ll give 20 points to anyone who will do it!
tensa zangetsu [6.8K]

what is it ??? ill edit this

3 0
3 years ago
Read 2 more answers
You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m
Leona [35]

Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, n_{Mg}, is given as follows;

n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

8 0
3 years ago
Please help me I'm really confused on how to do this. Can someone break it down for me? (stoichiometry)
bazaltina [42]

Answer:

so with every stoichiometry problem with a mass it will make it so you can do the conversion factor with reactants or products.

if you dont understand unit conversions try to study how to set it up. anyways

a.) C12H22O11 has a mass of 342.01 Grams per mole

divide 1.202 G by 342.01 G to get 0.004 miles

b.) you're just taking the AMU of each element in the chemical multiply it by how many there is of it in the chemical, then divide it by the mass of a mole of the chemical.

c.) you take your answers of part b and multiply them by Avogadro's number

6 0
4 years ago
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