Answer:
See explanation
Explanation:
Light is a form of energy. Both ultraviolet light and xrays are part of the electromagnetic spectrum.
As was said in the question, ultraviolet rays is absorbed by the rubber. We must know that prolonged exposure of this piece of rubber to incident ultraviolet light causes the vaporization of volatile materials in the rubber.
When volatile materials in the rubber vaporize, the rubber can become solid. Thus, ultraviolet light can cause rubber to become solid.
However, not all types of light can do this hence it does matter the type of light that falls on the rubber material.
1. She would want a balanced force so she doesn't fall but, well, keep her balance.
2. Frictional force because when an object slows down it's because a higher amount of friction is acting on it.
3. It would be magnitude and direction because is like the size of the object and they need to know how much force it will take to move it.
4. Is the same as 3...
5. A push and a pull are a force.
I hope this helps!
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. The type of medium that a compression wave can be transmitted through is liquids only. <span>When a wave moves faster than the local speed of sound in a fluid, it is a shock wave. Hope this answer helps. </span>
<span>
<span>
</span></span>Volume = 4/3 * PI * r^3
1.59 x 10^24 copper atoms = 2.64 moles of copper
Atomic Mass of copper = 63.55
2.64 * 63.55 = 167.77 grams of copper
Volume of Copper = Mass / Density
Volume of Copper = 167.77 grams / 8.96
Volume of Copper = <span>
<span>
18.72</span></span> cubic centimeters
r^3 = Volume / (4/3 * PI)
r^3 = 18.72 / 4.188
r^3 =
<span>
<span>
<span>
4.47
radius = </span></span></span><span><span><span>1.647</span> centimeters
</span></span>
Answer:
Explanation:
Hello!
In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:
We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:
Therefore, for is to compute the volume of the used base, we proceed as shown below:
And we plug in to obtain:
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