Answer:
3x^2 (y^5)^1/4 which is the first choice
Explanation:
The fourth root means that the bracket under has the root has a power of 1/4.
So, the given expression is:
(81 * x^8 * y^5)^1/4
Now, we will distribute the power as follows:
(81 * x^8 * y^5)^1/4 = (81)^1/4 * (x^8)^1/4 * (y^5)^1/4
= 3 * x^2 * y^5/4
This expression is equivalent to:
3x^2 (y^5)^1/4 which is the first choice
Hope this helps :)
Answer:
n= 1.25
Step-by-step explanation:
multiply both sides by 3 giving you 1.25
Answer:
![\mu = 20.3](https://tex.z-dn.net/?f=%20%5Cmu%20%3D%2020.3)
![\sigma = 4.9](https://tex.z-dn.net/?f=%5Csigma%20%3D%204.9)
And we can find the limits in order to consider values as significantly low and high like this:
![Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5](https://tex.z-dn.net/?f=%20Low%5Cleq%20%5Cmu%20-2%20%5Csigma%3D%2020.3-%202%2A4.9%20%3D%2010.5)
![High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1](https://tex.z-dn.net/?f=%20High%5Cgeq%20%5Cmu%20%2B2%20%5Csigma%3D%2020.3%2B%202%2A4.9%20%3D%2030.1)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.
For this case we have the mean and the deviation given:
![\mu = 20.3](https://tex.z-dn.net/?f=%20%5Cmu%20%3D%2020.3)
![\sigma = 4.9](https://tex.z-dn.net/?f=%5Csigma%20%3D%204.9)
And we can find the limits in order to consider values as significantly low and high like this:
![Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5](https://tex.z-dn.net/?f=%20Low%20%5Cleq%20%5Cmu%20-2%20%5Csigma%3D%2020.3-%202%2A4.9%20%3D%2010.5)
![High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1](https://tex.z-dn.net/?f=%20High%5Cgeq%20%5Cmu%20%2B2%20%5Csigma%3D%2020.3%2B%202%2A4.9%20%3D%2030.1)
To solve the problem, substitute the given points for x in the given equation to get
![-10=(-1)^2a+(-1)b+c\Rightarrow-10=a-b+c \\ -6=(1)^2a+(1)b+c\Rightarrow-6=a+b+c \\ -13=(2)^2a+(2)b+c\Rightarrow-13=4a+2b+c](https://tex.z-dn.net/?f=-10%3D%28-1%29%5E2a%2B%28-1%29b%2Bc%5CRightarrow-10%3Da-b%2Bc%20%5C%5C%20-6%3D%281%29%5E2a%2B%281%29b%2Bc%5CRightarrow-6%3Da%2Bb%2Bc%20%5C%5C%20-13%3D%282%29%5E2a%2B%282%29b%2Bc%5CRightarrow-13%3D4a%2B2b%2Bc)
Solving the three equations simultaneously, we have:
a = -3, b = 2 and c = -5
Therefore, the required equation is