Question

A basketball is dropped from top of the rim. It takes 1.3s to fall, what is the displacement?

Answer 1

Answer:

d = 8.45 m

Explanation:

Given that,

A basketball is dropped from top of the rim.

It takes 1.3s to fall.

We need to find the displacement of the basketball. Let the displacement is d. Using second equation of kinematics,

$d=ut+\dfrac{1}{2}at^2$

Where

u is the initial velocity, u = 0

a = g

So,

$d=\dfrac{1}{2}\times 10\times 1.3^2\\\\d=8.45\ m$

So, the displacement of the basketball is 8.45 m.