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AVprozaik [17]
2 years ago
8

There are lots of examples of ideal gases in the universe, and they exist in many different conditions. In this problem we will

examine what the temperature of these various phenomena are. Give an expression for the temperature of an ideal gas in terms of pressure P, particle density per unit volume rho and fundamental constants.
Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

P = ρRT/M

Explanation:

Ideal gas equation is given as follows generally:

PV = nRT (1)

P = pressure in the containing vessel

V = volume of the containing vessel

n = number of moles

R = gas constant

T = temperature in K

n = m/M

m = mass of the gas contained in the vessel in g

M = molar mass in g/mol

ρ = m/V

Density of the gas = ρ

Substituting for n in (1)

PV = mRT/M. (2)

Dividing equation (2) through by V

P = m/V ×RT/M

P = ρRT/M

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A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 214 N/C. The electrical p
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Answer:

 13.4 x 10 raise to power -19  C

Explanation:

. The distance moved by a charge in the direction of a uniform electric field is d= 1.8 cm =0.018 m

. The uniform electric field is  E = 214 N/M

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Let the magnitude of the charge of the moving particle be q

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51.63 x 10 power -19 = q(214)(0.018)

51.63 x 10 power -19 =3.852q

by making q the formular,

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A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s
Leokris [45]

Answer:

619.8 N

Explanation:

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At the beginning,

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Later, the radius of the string is decreased to

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Substituting these new data into the equation, we find the tension at which the string breaks:

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