I assume that the experiment is about calculating the enthalpy of a reaction.
If you consistently use the thermometer for all procedure in the experiment, the effect will be negligible because all temperature will be increased by 1.5 °C.
In enthalpy calculation, the energy is determined by the temperature differences. If the final and initial temperature increased by 1.5 °C, then the difference will not be changed.
Costs associated with product failures that occur after they have been sold to customers are known as external failure costs. These expenses cover the legal expenditures associated with customer lawsuits.
<h3>The expense of an external failure is an example of which of the following?</h3>
Liability claims. Warranty claims are regarded as a cost of external failure. It is a cost that the company incurs to replace and repair goods that customers have recently purchased.
<h3>What part of the external failure costs is this?</h3>
One element of the cost of quality is external failure costs, which are incurred when a subpar product is delivered to the client and malfunctions while being used. The warranty work and returns make up the majority of this expense. However, customer lawsuits could also be a possibility.
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Answer:
Explanation:
pH = − log [H+] , we can solve for [H+] as,
− pH = log [H+] ,
[H+] = 10^−pH,
so PH =2.4 in you case is
[H+] = 10^-2.4 =0.00398
The option are not correct it looks
