The company picnic cost $ 1300 for 80 employees
<em><u>Solution:</u></em>
Given that cost of a company picnic varies directly as the number of employees attending the picnic
Let "c" be the company picnic cost
Let "n" be the number of employees attending the picnic
Therefore,
![cost \propto \text{ number of employees attending picnic }](https://tex.z-dn.net/?f=cost%20%5Cpropto%20%5Ctext%7B%20number%20of%20employees%20attending%20picnic%20%7D)
![c \propto n\\\\c = kn](https://tex.z-dn.net/?f=c%20%5Cpropto%20n%5C%5C%5C%5Cc%20%3D%20kn)
Where "k" is the constant of proportionality
c = kn ---------- eqn 1
<em><u>Given that company picnic costs $487.50 for 30 employees</u></em>
Therefore substitute c = 487.50 and n = 30
![487.50 = k(30)\\\\k = \frac{487.50}{30} = 16.25](https://tex.z-dn.net/?f=487.50%20%3D%20k%2830%29%5C%5C%5C%5Ck%20%3D%20%5Cfrac%7B487.50%7D%7B30%7D%20%3D%2016.25)
<em><u>How much does a company picnic cost for 80 employees?</u></em>
Substitute n = 80 and k = 16.25 in eqn 1
![c = 16.25(80) = 1300](https://tex.z-dn.net/?f=c%20%3D%2016.25%2880%29%20%3D%201300)
Thus $ 1300 is the cost for 80 employees
Answer:
should be segment BT, that's what i put and it was right. hope this helps
Step-by-step explanation:
X^1/2 - x
-2x^3 - x^1/2 - x
-2x^3 - 2x
i think this is it
Answer:
Option D = 16π/3 ft
Step-by-step explanation:
Arc length formula is written Mathematically as:
Arc length = 2πr × θ /360
r = 4 ft
θ = Central angle in degrees = 240°
2 × π × 4 × 240/360
8π × 240/360
8π × 20/30
16π/3 ft
So, the arc length is 16π/3 ft
Answer:
whats the question and are you supposed to type in the answer or do they have a choice?